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Data Structures Theoryknowledge~10 mins

Hash table applications in Data Structures Theory - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a hash table that stores key-value pairs.

Data Structures Theory
hash_table = [1]()
Drag options to blanks, or click blank then click option'
Adict
Bset
Clist
Dtuple
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Using list instead of dict, which does not support key-value pairs.
Using set, which stores only unique values without keys.
2fill in blank
medium

Complete the code to check if a key exists in a hash table.

Data Structures Theory
if [1] in hash_table:
Drag options to blanks, or click blank then click option'
Aitem
Bindex
Ckey
Dvalue
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Checking for a value instead of a key.
Using an index which is not applicable in hash tables.
3fill in blank
hard

Fix the error in the code to add a key-value pair to the hash table.

Data Structures Theory
hash_table[[1]] = 'value'
Drag options to blanks, or click blank then click option'
A'key'
Bkey
Cvalue
Ditem
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Using an unquoted key which causes a NameError.
Using a value as a key.
4fill in blank
hard

Fill both blanks to create a hash table comprehension that maps words to their lengths for words longer than 3 characters.

Data Structures Theory
{word: [1] for word in words if len(word) [2] 3}
Drag options to blanks, or click blank then click option'
Alen(word)
B<
C>
Dword
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Using the word itself instead of its length as the value.
Using the wrong comparison operator in the condition.
5fill in blank
hard

Fill all three blanks to create a hash table that stores uppercase keys and their values only if the value is positive.

Data Structures Theory
{ [1]: [2] for [3], [2] in data.items() if [2] > 0 }
Drag options to blanks, or click blank then click option'
Akey.upper()
Bvalue
Ckey
Ditem
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Using the same variable name for key and value.
Not converting keys to uppercase.
Using incorrect variable names in the loop.

Practice

(1/5)
1. What is the main advantage of using a hash table in data storage?
easy
A. It encrypts data for security
B. It stores data in a sorted order automatically
C. It compresses data to save space
D. It allows very fast data lookup using keys

Solution

  1. Step 1: Understand hash table purpose

    Hash tables use keys to quickly find stored data without searching all items.
  2. Step 2: Compare options with hash table features

    Only fast lookup matches hash table's main advantage; sorting, compression, encryption are unrelated.
  3. Final Answer:

    It allows very fast data lookup using keys -> Option D
  4. Quick Check:

    Fast lookup = It allows very fast data lookup using keys [OK]
Hint: Hash tables are all about quick key-based access [OK]
Common Mistakes:
  • Confusing hash tables with sorted data structures
  • Thinking hash tables compress or encrypt data
  • Assuming hash tables store data in order
2. Which of the following is the correct way to check if a key exists in a hash table?
easy
A. if hash_table.has_key(key):
B. if key in hash_table:
C. if key.exists(hash_table):
D. if hash_table.contains(key):

Solution

  1. Step 1: Recall common syntax for key existence

    In many languages like Python, 'if key in hash_table:' is the standard way.
  2. Step 2: Evaluate other options

    Methods like has_key() are outdated or language-specific; others are incorrect syntax.
  3. Final Answer:

    if key in hash_table: -> Option B
  4. Quick Check:

    Standard syntax = if key in hash_table: [OK]
Hint: Use 'in' keyword to check keys in hash tables [OK]
Common Mistakes:
  • Using outdated methods like has_key()
  • Trying non-existent methods like exists() or contains()
  • Confusing key existence with value checks
3. Consider a hash table used to count word occurrences in a text. After processing the text, what will be the value of counts['apple'] if the word 'apple' appears 3 times?
medium
A. 3
B. 1
C. 0
D. undefined

Solution

  1. Step 1: Understand counting with hash tables

    Each time 'apple' appears, the count increments by 1 in the hash table.
  2. Step 2: Calculate final count for 'apple'

    Since 'apple' appears 3 times, the count stored is 3.
  3. Final Answer:

    3 -> Option A
  4. Quick Check:

    Count of 'apple' = 3 [OK]
Hint: Count increments match word occurrences [OK]
Common Mistakes:
  • Assuming count starts at 0 and stays 0
  • Confusing count with boolean existence
  • Thinking the value is undefined if key exists
4. A hash table implementation is returning incorrect results when two different keys produce the same hash value. What is the likely problem?
medium
A. The hash function is too slow
B. Keys are not strings
C. Collision handling is missing or incorrect
D. The table size is too large

Solution

  1. Step 1: Identify issue with same hash values

    When two keys have the same hash, it's called a collision.
  2. Step 2: Understand collision handling importance

    If collisions are not handled properly, data can overwrite or be lost, causing errors.
  3. Final Answer:

    Collision handling is missing or incorrect -> Option C
  4. Quick Check:

    Collision handling = missing or incorrect [OK]
Hint: Collisions need special handling to avoid errors [OK]
Common Mistakes:
  • Blaming hash function speed instead of collision handling
  • Thinking key type causes collisions
  • Assuming larger table size fixes collisions alone
5. You want to find all unique items from a large list quickly. Which hash table application is best suited for this task?
hard
A. Using a hash table to store items as keys and ignore duplicates
B. Using a hash table to count occurrences of each item
C. Using a hash table to sort the list items
D. Using a hash table to encrypt the list items

Solution

  1. Step 1: Understand the goal of finding unique items

    We want to keep only one copy of each item, ignoring duplicates.
  2. Step 2: Choose hash table usage that stores keys uniquely

    Storing items as keys automatically ignores duplicates because keys are unique.
  3. Step 3: Eliminate other options

    Counting occurrences is extra work; sorting or encrypting does not find unique items efficiently.
  4. Final Answer:

    Using a hash table to store items as keys and ignore duplicates -> Option A
  5. Quick Check:

    Unique items = store as keys ignoring duplicates [OK]
Hint: Store items as keys to keep only unique entries [OK]
Common Mistakes:
  • Using counting when only uniqueness is needed
  • Thinking sorting helps find unique items faster
  • Confusing encryption with uniqueness
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10 questions~5 mineasy hard