Common linked list patterns (runner technique) in Data Structures Theory - Time & Space Complexity

Time Complexity: Common linked list patterns (runner technique)

O(n)

Understanding Time Complexity

When working with linked lists, the runner technique helps us move through the list efficiently.

We want to know how the time needed changes as the list gets longer.

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

Node* slow = head;
Node* fast = head;
while (fast != nullptr && fast->next != nullptr) {
    slow = slow->next;
    fast = fast->next->next;
}
// slow now points to the middle node
    

This code uses two pointers moving at different speeds to find the middle of a linked list.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: Moving the fast and slow pointers through the list.
• How many times: The loop runs about half the length of the list because fast moves two steps each time.

How Execution Grows With Input

As the list gets longer, the loop runs more times, but only about half as many as the list length.

Input Size (n)	Approx. Operations
10	5
100	50
1000	500

Pattern observation: The number of steps grows roughly in direct proportion to the list size.

Final Time Complexity

Time Complexity: O(n)

This means the time to find the middle grows linearly as the list gets longer.

Common Mistake

[X] Wrong: "Because the fast pointer moves two steps, the time complexity is O(n/2), which is faster than O(n)."

[OK] Correct: We ignore constants in time complexity, so O(n/2) is the same as O(n). The time still grows linearly with input size.

Interview Connect

Understanding the runner technique shows you can handle linked lists efficiently, a common skill interviewers look for.

Self-Check

"What if the fast pointer moved three steps at a time instead of two? How would the time complexity change?"

Practice

1. What is the main purpose of the runner technique in linked lists?

easy

A. To use two pointers moving at different speeds to solve problems efficiently

B. To sort the linked list elements in ascending order

C. To convert a linked list into an array

D. To delete all nodes from the linked list

Solution

1. Step 1: Understand the runner technique concept

   The runner technique involves two pointers moving through the list at different speeds to solve problems like finding the middle or detecting loops.

2. Step 2: Identify the main purpose

   This technique is used to efficiently solve linked list problems in one pass without extra memory.

3. Final Answer:

   To use two pointers moving at different speeds to solve problems efficiently -> Option A

4. Quick Check:

   Runner technique = two pointers at different speeds [OK]

Hint: Runner technique uses two pointers at different speeds [OK]

Common Mistakes:

• Thinking it sorts the list
• Confusing it with list conversion
• Assuming it deletes nodes

2. Which of the following is the correct way to initialize two pointers for the runner technique in a singly linked list?

easy

A. slow = head; fast = null

B. slow = head; fast = head.next

C. slow = null; fast = head

D. slow = head.next; fast = head

Solution

1. Step 1: Understand pointer initialization for runner technique

   Typically, slow pointer starts at head, and fast pointer starts at the next node to move faster.

2. Step 2: Check each option

   slow = head; fast = head.next correctly sets slow to head and fast to head.next, allowing fast to move two steps ahead.

3. Final Answer:

   slow = head; fast = head.next -> Option B

4. Quick Check:

   Fast pointer starts one step ahead [OK]

Hint: Fast pointer starts one node ahead of slow [OK]

Common Mistakes:

• Setting slow ahead of fast
• Starting pointers at null
• Both pointers starting at same node without offset

3. Consider the following linked list: 1 -> 2 -> 3 -> 4 -> 5 -> null.
Using the runner technique where slow moves one step and fast moves two steps, what value will slow point to when fast reaches the end?

medium

A. 5

B. 2

C. 4

D. 3

Solution

1. Step 1: Trace slow and fast pointers through the list

   Start: slow=1, fast=1
   Move 1: slow=2, fast=3
   Move 2: slow=3, fast=5
   Move 3: fast tries to move two steps but reaches null, stop.

2. Step 2: Identify slow pointer's position when fast ends

   When fast reaches the end (node 5), slow is at node 3.

3. Final Answer:

   3 -> Option D

4. Quick Check:

   Middle node = 3 [OK]

Hint: Slow pointer at middle when fast reaches end [OK]

Common Mistakes:

• Stopping too early and picking 2
• Assuming slow moves as fast as fast pointer
• Confusing node values with pointer positions

4. In the runner technique, if the fast pointer is not moving two steps but only one step each time, what problem might occur?

medium

A. The fast pointer will never reach the end, causing an infinite loop

B. The slow pointer will move too fast and skip nodes

C. The technique will still work correctly without issues

D. The slow pointer will become null immediately

Solution

1. Step 1: Understand the role of fast pointer speed

   The fast pointer moves two steps to catch up or reach the end faster than slow pointer.

2. Step 2: Analyze effect if fast moves only one step

   If fast moves one step, both pointers move at same speed, so fast never overtakes slow, possibly causing infinite loop in cycle detection.

3. Final Answer:

   The fast pointer will never reach the end, causing an infinite loop -> Option A

4. Quick Check:

   Fast pointer speed crucial to avoid infinite loops [OK]

Hint: Fast pointer must move faster to avoid infinite loops [OK]

Common Mistakes:

• Assuming slow pointer moves too fast
• Thinking technique works with equal speeds
• Ignoring infinite loop possibility

5. You want to detect if a linked list has a cycle using the runner technique. Which of the following best describes the condition to confirm a cycle?

hard

A. The slow pointer reaches the end of the list

B. The fast pointer becomes null

C. The slow and fast pointers meet at the same node

D. The slow pointer moves two steps at a time

Solution

1. Step 1: Recall cycle detection with runner technique

   If a cycle exists, fast pointer will eventually catch up to slow pointer inside the loop.

2. Step 2: Identify the condition for cycle detection

   The pointers meeting at the same node means the list has a cycle.

3. Final Answer:

   The slow and fast pointers meet at the same node -> Option C

4. Quick Check:

   Pointers meeting = cycle detected [OK]

Hint: Cycle detected when pointers meet [OK]

Common Mistakes:

• Thinking fast pointer reaching null means cycle
• Assuming slow pointer reaches end means cycle
• Confusing pointer speeds