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Data Structures Theoryknowledge~10 mins

Circular queue in Data Structures Theory - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the sentence to define a circular queue.

Data Structures Theory
A circular queue connects the last position back to the [1] position.
Drag options to blanks, or click blank then click option'
Afirst
Bsecond
Cmiddle
Dlast
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Choosing 'last' because it sounds like the end.
Confusing 'middle' with the start.
2fill in blank
medium

Complete the sentence about the main advantage of a circular queue.

Data Structures Theory
A circular queue efficiently uses memory by reusing [1] positions after they are freed.
Drag options to blanks, or click blank then click option'
Aall
Bempty
Cfull
Dnew
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Choosing 'full' because it sounds like the queue is busy.
Choosing 'new' which is unrelated to reuse.
3fill in blank
hard

Fix the error in the statement about circular queue pointers.

Data Structures Theory
In a circular queue, the [1] pointer moves forward and wraps around to the start when it reaches the end.
Drag options to blanks, or click blank then click option'
Amiddle
Bfront
Crear
Dsize
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Choosing 'front' which is used for removing elements.
Choosing 'size' which is not a pointer.
4fill in blank
hard

Fill both blanks to complete the condition that checks if a circular queue is full.

Data Structures Theory
The queue is full if (rear + 1) [1] size and front [2] rear.
Drag options to blanks, or click blank then click option'
Amod
B==
C!=
D+
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Using '+' instead of 'mod' for wrapping.
Using '!=' instead of '==' for comparison.
5fill in blank
hard

Fill all three blanks to complete the formula for the number of elements in a circular queue.

Data Structures Theory
count = (rear - front + [1]) [2] size [3] 1
Drag options to blanks, or click blank then click option'
Asize
B%
C+
D-
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Using '+' instead of '-' at the end.
Omitting the modulo operation.

Practice

(1/5)
1. What is the main advantage of a circular queue compared to a regular linear queue?
easy
A. It allows storing different data types in the same queue.
B. It efficiently reuses empty space by connecting the end to the start.
C. It automatically sorts elements while enqueuing.
D. It requires shifting elements after every dequeue operation.

Solution

  1. Step 1: Understand the structure of a circular queue

    A circular queue connects the last position back to the first, forming a circle.
  2. Step 2: Identify the advantage over a linear queue

    This connection allows the queue to reuse spaces freed by dequeued elements without shifting.
  3. Final Answer:

    It efficiently reuses empty space by connecting the end to the start. -> Option B
  4. Quick Check:

    Circular queue = space reuse [OK]
Hint: Circular queue wraps around to reuse space [OK]
Common Mistakes:
  • Thinking it sorts elements automatically
  • Believing it stores multiple data types
  • Assuming it shifts elements after dequeue
2. Which of the following is the correct way to update the rear pointer in a circular queue after an enqueue operation?
easy
A. rear = (rear + 1) % size
B. rear = rear + 1
C. rear = rear - 1
D. rear = size - rear

Solution

  1. Step 1: Recall how circular queue pointers move

    In a circular queue, pointers wrap around using modulo arithmetic to stay within bounds.
  2. Step 2: Apply modulo to update rear pointer

    After enqueue, rear moves to (rear + 1) modulo the queue size to wrap if needed.
  3. Final Answer:

    rear = (rear + 1) % size -> Option A
  4. Quick Check:

    Rear update uses modulo [OK]
Hint: Use modulo (%) to wrap rear pointer [OK]
Common Mistakes:
  • Incrementing rear without modulo
  • Decrementing rear after enqueue
  • Using subtraction instead of modulo
3. Consider a circular queue of size 5 with front = 3 and rear = 1. Which of the following statements is true about the queue state?
medium
A. The queue is empty.
B. The queue is full.
C. The queue has 3 elements.
D. The queue has 4 elements.

Solution

  1. Step 1: Understand front and rear positions in circular queue

    Front at 3 and rear at 1 means rear has wrapped around past front.
  2. Step 2: Calculate number of elements using formula

    Number of elements = (rear - front + size) % size = (1 - 3 + 5) % 5 = 3 % 5 = 3.
  3. Final Answer:

    The queue has 3 elements. -> Option C
  4. Quick Check:

    Elements count = 3 [OK]
Hint: Use (rear - front + size) % size to count elements [OK]
Common Mistakes:
  • Confusing full and empty conditions
  • Ignoring modulo in calculation
  • Assuming rear < front means empty
4. Given this code snippet for dequeue in a circular queue, what is the error?
if front == -1:
    print("Queue is empty")
else:
    data = queue[front]
    if front == rear:
        front = rear = -1
    else:
        front = (front + 1) % size
medium
A. The code does not return or use the dequeued data.
B. The front pointer update should use rear instead of front.
C. The condition to check empty queue is incorrect.
D. The rear pointer should be incremented after dequeue.

Solution

  1. Step 1: Analyze the dequeue operation steps

    The code checks if queue is empty, retrieves data, updates pointers correctly.
  2. Step 2: Identify missing usage of dequeued data

    Though data is assigned, it is neither returned nor used, so the operation loses the dequeued value.
  3. Final Answer:

    The code does not return or use the dequeued data. -> Option A
  4. Quick Check:

    Dequeue must return data [OK]
Hint: Always return dequeued element [OK]
Common Mistakes:
  • Not returning dequeued value
  • Incorrect pointer updates
  • Incrementing rear on dequeue
5. You have a circular queue of size 6. Initially, front = 0 and rear = 4. You perform two dequeue operations followed by three enqueue operations. What will be the final positions of front and rear?
hard
A. front = 1, rear = 2
B. front = 2, rear = 0
C. front = 0, rear = 5
D. front = 2, rear = 1

Solution

  1. Step 1: Update front after two dequeues

    Each dequeue moves front by 1 modulo size: front = (0 + 2) % 6 = 2.
  2. Step 2: Update rear after three enqueues

    Each enqueue moves rear by 1 modulo size: rear = (4 + 3) % 6 = 7 % 6 = 1.
  3. Final Answer:

    front = 2, rear = 1 -> Option D
  4. Quick Check:

    Front and rear updated with modulo [OK]
Hint: Add operations to pointers using modulo size [OK]
Common Mistakes:
  • Not using modulo for pointer wrap-around
  • Mixing front and rear updates
  • Forgetting to update pointers after each operation
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10 questions~5 mineasy hard