Why text data requires special handling in Data Analysis Python - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to convert a text column to lowercase.

Data Analysis Python

df['text'] = df['text'].[1]()

Drag options to blanks, or click blank then click option'

Alower

Bupper

Cstrip

Dsplit

Attempts:

3 left

💡 Hint

Common Mistakes

Using upper() changes text to uppercase, which is not standard for normalization.

Using strip() removes spaces but does not change case.

Using split() breaks text into words, not case conversion.

Using lower() converts all text to lowercase, which helps standardize text data for analysis.

2fill in blank

medium

Complete the code to remove punctuation from a text string using Python's string module.

Data Analysis Python

import string
text = 'Hello, world!'
clean_text = ''.join(char for char in text if char not in [1])

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Astring.ascii_letters

Bstring.digits

Cstring.punctuation

Dstring.whitespace

Attempts:

3 left

💡 Hint

Common Mistakes

Using string.whitespace removes spaces, which are needed to separate words.

Using string.ascii_letters removes letters, which we want to keep.

Using string.digits removes numbers, which may or may not be desired.

string.punctuation contains all punctuation characters. Filtering them out cleans the text.

3fill in blank

hard

Fix the error in the code to split text into words correctly.

Data Analysis Python

text = 'Data science is fun'
words = text.[1](' ')

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Asplit

Bjoin

Creplace

Dstrip

Attempts:

3 left

💡 Hint

Common Mistakes

Using join() combines a list into a string, not splitting.

Using replace() changes characters but does not split.

Using strip() removes spaces at ends but does not split.

The split(' ') method breaks the string into a list of words separated by spaces.

4fill in blank

hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 characters.

Data Analysis Python

words = ['data', 'is', 'fun', 'science']
lengths = {word: [1] for word in words if len(word) [2] 3}

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Alen(word)

Bword

C>

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of len(word) gives the word itself, not its length.

Using '<=' includes short words, not filtering correctly.

We use len(word) to get word length and filter words with length greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary of uppercase words with length greater than 2.

Data Analysis Python

words = ['cat', 'is', 'big', 'dog']
result = [1] for word in words if len(word) [2] 2]
result = {w.[3](): w for w in result}

Drag options to blanks, or click blank then click option'

A[word.upper()

B>

Cupper

Dword.upper()

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'word.upper()' in the first blank is incorrect syntax for list comprehension start.

Using '<' instead of '>' filters wrong words.

Using 'upper()' with parentheses in dictionary key causes error; method name only is needed.

First, we create a list of words with length greater than 2 using a list comprehension starting with [word.upper(). Then we filter with >. Finally, we create a dictionary with keys as uppercase words using upper method.