Why efficiency matters with large datasets in Data Analysis Python - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a list of squares for numbers 1 to 5.

Data Analysis Python

squares = [x[1]2 for x in range(1, 6)]
print(squares)

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A//

B+

C*

D**

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiplication (*) instead of exponentiation (**)

Using addition (+) which adds numbers instead of squaring

Using ** raises x to the power of 2, which calculates squares.

2fill in blank

medium

Complete the code to filter numbers greater than 10 from the list.

Data Analysis Python

numbers = [5, 12, 7, 18, 3]
filtered = [n for n in numbers if n [1] 10]
print(filtered)

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A<

B>

C==

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using less than (<) which selects smaller numbers

Using equality (==) which selects only numbers equal to 10

The operator > selects numbers greater than 10.

3fill in blank

hard

Fix the error in the code to calculate the average of a list.

Data Analysis Python

data = [10, 20, 30]
avg = sum(data) [1] len(data)
print(avg)

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A/

B-

C+

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using addition (+) or multiplication (*) instead of division

Using subtraction (-) which is incorrect here

To find the average, divide the sum by the number of items using /.

4fill in blank

hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 letters.

Data Analysis Python

words = ['data', 'is', 'fun', 'and', 'big']
lengths = {word: [1] for word in words if len(word) [2] 3}
print(lengths)

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Alen(word)

Bword

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length

Using < instead of > which selects shorter words

The dictionary maps each word to its length using len(word). The condition > selects words longer than 3 letters.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than 0.

Data Analysis Python

data = {'a': 1, 'b': -2, 'c': 3}
result = { [1]: [2] for k, v in data.items() if v [3] 0 }
print(result)

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Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using original keys instead of uppercase

Filtering values less than or equal to zero

Swapping keys and values in the dictionary

The dictionary comprehension uses k.upper() for uppercase keys, v for values, and filters values greater than 0 with >.