Creating interaction features in Data Analysis Python - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a new feature by multiplying 'age' and 'income'.

Data Analysis Python

df['age_income'] = df['age'] [1] df['income']

Drag options to blanks, or click blank then click option'

A+

B-

C*

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' instead of '*' which adds instead of multiplies.

Using '/' which divides and may cause errors if denominator has zeros.

Multiplying 'age' and 'income' creates an interaction feature that combines both effects.

2fill in blank

medium

Complete the code to create an interaction feature by concatenating 'city' and 'job' as strings.

Data Analysis Python

df['city_job'] = df['city'] [1] df['job']

Drag options to blanks, or click blank then click option'

A//

B*

C-

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using '*' which causes an error for strings.

Using '-' which is invalid for strings.

Using '+' concatenates two string columns to create an interaction feature.

3fill in blank

hard

Fix the error in the code to create an interaction feature by multiplying 'height' and 'weight'.

Data Analysis Python

df['height_weight'] = df['height'] [1] df['weight']

Drag options to blanks, or click blank then click option'

A*

B-

C+

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' which adds instead of multiplying.

Using '/' which divides and is incorrect here.

Multiplying 'height' and 'weight' creates an interaction feature that combines both effects.

4fill in blank

hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 characters.

Data Analysis Python

lengths = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' causing wrong filtering.

Using 'word' instead of 'len(word)' for the value.

The dictionary comprehension maps each word to its length if the word length is greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than zero.

Data Analysis Python

result = { [1]: [2] for k, v in data.items() if v [3] 0}

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'k' instead of 'k.upper()' for keys.

Using '<' or other operators instead of '>' for filtering.

Using 'k' as value instead of 'v'.

This dictionary comprehension creates keys as uppercase strings and includes only items where the value is greater than zero.

Practice

1. What is the main purpose of creating interaction features in data analysis?

easy

A. To capture the combined effect of two or more features on the target

B. To remove irrelevant features from the dataset

C. To reduce the size of the dataset by merging columns

D. To convert categorical data into numerical data

Solution

1. Step 1: Understand interaction features

   Interaction features combine two or more features to capture their joint effect on the target variable.

2. Step 2: Compare options

   Only To capture the combined effect of two or more features on the target describes capturing combined effects, which is the purpose of interaction features.

3. Final Answer:

   To capture the combined effect of two or more features on the target -> Option A

4. Quick Check:

   Interaction features capture combined effects = A [OK]

Hint: Interaction features combine columns to show joint effects [OK]

Common Mistakes:

• Confusing interaction features with feature selection
• Thinking interaction features reduce dataset size
• Mixing interaction features with encoding categorical data

2. Which of the following Python code snippets correctly creates an interaction feature df['A_B'] by multiplying columns 'A' and 'B' in a DataFrame df?

easy

A. df['A_B'] = df['A'] * df['B']

B. df['A_B'] = df['A'].concat(df['B'])

C. df['A_B'] = df['A'].append(df['B'])

D. df['A_B'] = df['A'] + df['B']

Solution

1. Step 1: Identify correct operation for interaction

   Interaction features are often created by multiplying columns to capture joint effects.

2. Step 2: Check code syntax

   df['A_B'] = df['A'] * df['B'] uses multiplication (*) between columns, which is correct syntax in pandas.

3. Final Answer:

   df['A_B'] = df['A'] * df['B'] -> Option A

4. Quick Check:

   Multiplying columns creates interaction feature = D [OK]

Hint: Multiply columns with * to create interaction features [OK]

Common Mistakes:

• Using + instead of * for interaction
• Using append or concat which are for combining rows or DataFrames
• Syntax errors from wrong method calls

3. Given the DataFrame df below:

   A  B
0  2  3
1  4  5
2  6  7

What will be the output of df['A_B'] = df['A'] * df['B']; df['A_B'].tolist()?

medium

A. [2, 4, 6]

B. [5, 9, 13]

C. [6, 20, 42]

D. [3, 5, 7]

Solution

1. Step 1: Multiply each row's values in columns A and B

   Row 0: 2*3=6, Row 1: 4*5=20, Row 2: 6*7=42

2. Step 2: Convert the new column to list

   The list is [6, 20, 42]

3. Final Answer:

   [6, 20, 42] -> Option C

4. Quick Check:

   Row-wise multiplication = [6, 20, 42] [OK]

Hint: Multiply row values, then list() to see results [OK]

Common Mistakes:

• Adding instead of multiplying values
• Confusing column names or indices
• Returning original columns instead of interaction

4. Consider this code snippet to create an interaction feature:

df['A_B'] = df['A'] * df['B']
df['A_B'] = df['A_B'].apply(lambda x: x if x > 10 else 0)

What is the error in this code if df['A'] and df['B'] contain numeric values?

medium

A. The apply function should be used on rows, not on a column

B. No error; the code correctly creates and modifies the interaction feature

C. The lambda function syntax is incorrect

D. Multiplying columns directly causes a runtime error

Solution

1. Step 1: Check multiplication of columns

   Multiplying two numeric columns in pandas works correctly and creates a new column.

2. Step 2: Check apply with lambda on the new column

   Applying a lambda function to modify values conditionally is valid syntax and works on a Series.

3. Final Answer:

   No error; the code correctly creates and modifies the interaction feature -> Option B

4. Quick Check:

   Column multiplication and apply lambda are valid = A [OK]

Hint: apply with lambda on Series is valid for conditional changes [OK]

Common Mistakes:

• Thinking apply only works on DataFrame rows
• Assuming multiplication causes errors with numeric columns
• Misreading lambda function syntax

5. You have a dataset with columns age and income. You want to create an interaction feature to capture how age modifies the effect of income on spending. Which code snippet correctly creates this interaction feature and then normalizes it by dividing by the maximum value?

hard

A. df['age_income'] = (df['age'] * df['income']) / df['age'].max()

B. df['age_income'] = df['age'] * df['income'] / df['income'].min()

C. df['age_income'] = (df['age'] + df['income']) / df['income'].max()

D. df['age_income'] = (df['age'] * df['income']) / (df['age'] * df['income']).max()

Solution

1. Step 1: Create interaction by multiplying age and income

   Multiplying captures how age modifies income effect.

2. Step 2: Normalize by dividing by max of the interaction feature

   Dividing by (df['age'] * df['income']).max() scales the new feature between 0 and 1.

3. Final Answer:

   df['age_income'] = (df['age'] * df['income']) / (df['age'] * df['income']).max() -> Option D

4. Quick Check:

   Multiply then normalize by max interaction = B [OK]

Hint: Multiply columns then divide by max of product to normalize [OK]

Common Mistakes:

• Normalizing by max of only one column instead of product
• Adding columns instead of multiplying for interaction
• Using min instead of max for normalization