Single and multiple column grouping in Data Analysis Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to group the DataFrame by the 'Category' column.

Data Analysis Python

grouped = df.groupby([1])

Drag options to blanks, or click blank then click option'

A'Date'

B'Value'

C'Category'

D'Index'

Attempts:

3 left

💡 Hint

Common Mistakes

Using a column name that does not exist in the DataFrame.

Not using quotes around the column name.

To group data by a single column, you pass the column name as a string to groupby(). Here, 'Category' is the correct column to group by.

2fill in blank

medium

Complete the code to group the DataFrame by both 'Category' and 'Region' columns.

Data Analysis Python

grouped = df.groupby([1])

Drag options to blanks, or click blank then click option'

A('Category', 'Region')

B'Category'

C'Category, Region'

D['Category', 'Region']

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a single string with comma-separated column names.

Using a tuple instead of a list.

To group by multiple columns, pass a list of column names to groupby(). The list should be inside square brackets.

3fill in blank

hard

Fix the error in the code to correctly group by 'Category' and calculate the mean.

Data Analysis Python

result = df.groupby([1]).mean()

Drag options to blanks, or click blank then click option'

A['Category']

B'Category'

CCategory

D'Category', 'Region'

Attempts:

3 left

💡 Hint

Common Mistakes

Passing multiple columns as separate arguments without a list.

Not using quotes around the column name.

The groupby() method expects a single column name as a string or a list of strings. Here, to group by one column, pass the column name as a string.

4fill in blank

hard

Fill both blanks to create a dictionary with word lengths for words longer than 3 characters.

Data Analysis Python

lengths = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' in the condition.

Using the word itself instead of its length as the value.

The dictionary comprehension maps each word to its length using len(word). The condition filters words with length greater than 3 using the '>' operator.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys, values, and filter condition.

Data Analysis Python

result = [1]: [2] for k, v in data.items() if v [3] 0}

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'k' instead of 'k.upper()' for keys.

Using '<' instead of '>' in the condition.

The dictionary comprehension uses k.upper() to make keys uppercase, keeps values as v, and filters items where v > 0.

Practice

1. What does the groupby() function do in data analysis with pandas?

easy

A. It groups data based on one or more columns to summarize it.

B. It sorts the data alphabetically.

C. It deletes duplicate rows from the data.

D. It changes the data type of columns.

Solution

1. Step 1: Understand the purpose of grouping

   Grouping means collecting rows that share the same value in one or more columns.

2. Step 2: Role of groupby() in pandas

   The groupby() function in pandas helps to split data into groups based on column values for aggregation or analysis.

3. Final Answer:

   It groups data based on one or more columns to summarize it. -> Option A

4. Quick Check:

   Grouping = Summarizing data by columns [OK]

Hint: Remember: groupby = group rows by column values [OK]

Common Mistakes:

• Thinking groupby sorts data
• Confusing groupby with removing duplicates
• Assuming groupby changes data types

2. Which of the following is the correct syntax to group a pandas DataFrame df by two columns 'A' and 'B'?

easy

A. df.groupby(['A', 'B'])

B. df.groupby('A', 'B')

C. df.group_by(['A', 'B'])

D. df.groupby(['A' & 'B'])

Solution

1. Step 1: Check pandas groupby syntax for multiple columns

   To group by multiple columns, pass a list of column names inside groupby: df.groupby(['A', 'B']).

2. Step 2: Identify incorrect syntax options

   df.groupby('A', 'B') misses list brackets, df.group_by(['A', 'B']) uses wrong method name, df.groupby(['A' & 'B']) uses invalid operator inside list.

3. Final Answer:

   df.groupby(['A', 'B']) -> Option A

4. Quick Check:

   Multiple columns = list inside groupby [OK]

Hint: Use a list of columns inside groupby for multiple columns [OK]

Common Mistakes:

• Passing columns as separate arguments instead of list
• Using wrong method name like group_by
• Using operators inside list instead of commas

3. Given the DataFrame df below:

   City  Sales  Quantity
0  NY    100    2
1  LA    200    3
2  NY    150    1
3  LA    100    4
4  NY    200    2

What is the output of df.groupby('City')['Sales'].sum()?

medium

A. City
LA 400
NY 350
Name: Sales, dtype: int64

B. City
LA 400
NY 450
Name: Sales, dtype: int64

C. City
LA 300
NY 350
Name: Sales, dtype: int64

D. City
LA 300
NY 450
Name: Sales, dtype: int64

Solution

1. Step 1: Group data by 'City' and sum 'Sales'

   Group rows by City: LA rows have Sales 200 and 100, sum = 300; NY rows have Sales 100, 150, 200, sum = 450.

2. Step 2: Write the resulting Series

   The result shows sums per city: LA 300, NY 450, with City as index and Sales as name.

3. Final Answer:

   City LA 300 NY 450 Name: Sales, dtype: int64 -> Option D

4. Quick Check:

   Sum Sales by City = LA:300, NY:450 [OK]

Hint: Add values per group to find sum quickly [OK]

Common Mistakes:

• Adding wrong rows for each city
• Mixing sum of Sales with Quantity
• Confusing index and values in output

4. What is wrong with this code snippet?

df.groupby('Category', 'Type').mean()

medium

A. Category and Type columns must be numeric.

B. mean() cannot be used after groupby.

C. groupby expects a list for multiple columns, not separate arguments.

D. groupby requires column names as integers.

Solution

1. Step 1: Check groupby syntax for multiple columns

   When grouping by multiple columns, pass a list: df.groupby(['Category', 'Type']). Passing separate arguments causes error.

2. Step 2: Verify other options

   mean() is valid after groupby; columns can be non-numeric but mean applies only to numeric; column names are strings, not integers.

3. Final Answer:

   groupby expects a list for multiple columns, not separate arguments. -> Option C

4. Quick Check:

   Multiple columns need list in groupby [OK]

Hint: Use list brackets for multiple columns in groupby [OK]

Common Mistakes:

• Passing multiple columns as separate arguments
• Thinking mean() is invalid after groupby
• Assuming column names must be integers

5. You have a sales DataFrame df with columns 'Region', 'Product', and 'Revenue'. You want to find the average revenue per region and product, but only for products with total revenue above 1000. Which code correctly achieves this?

hard

A. df.groupby(['Region', 'Product'])['Revenue'].mean()[df['Revenue'].sum() > 1000]

B. df.groupby(['Region', 'Product']).filter(lambda x: x['Revenue'].sum() > 1000).groupby(['Region', 'Product'])['Revenue'].mean()

C. df.groupby(['Region', 'Product'])['Revenue'].sum().mean() > 1000

D. df.groupby(['Region', 'Product'])['Revenue'].mean().filter(lambda x: x > 1000)

Solution

1. Step 1: Filter groups with total revenue above 1000

   Use filter() with a lambda to keep groups where sum of Revenue > 1000.

2. Step 2: Calculate mean revenue per filtered group

   After filtering, group again by Region and Product and calculate mean Revenue.

3. Step 3: Analyze other options

   df.groupby(['Region', 'Product'])['Revenue'].mean()[df['Revenue'].sum() > 1000] uses total Revenue sum instead of per-group sum, returning all means or none; df.groupby(['Region', 'Product'])['Revenue'].sum().mean() > 1000 computes mean of sums, not per group; df.groupby(['Region', 'Product'])['Revenue'].mean().filter(lambda x: x > 1000) filters means > 1000, not sums.

4. Final Answer:

   df.groupby(['Region', 'Product']).filter(lambda x: x['Revenue'].sum() > 1000).groupby(['Region', 'Product'])['Revenue'].mean() -> Option B

5. Quick Check:

   Filter groups by sum, then compute mean [OK]

Hint: Use filter() to keep groups before aggregation [OK]

Common Mistakes:

• Trying to filter after aggregation with mismatched indexes
• Confusing mean of sums with sum of means
• Filtering on mean instead of sum