Bird
Raised Fist0
Data Analysis Pythondata~10 mins

groupby() basics in Data Analysis Python - Interactive Code Practice

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to group the DataFrame by the 'Category' column.

Data Analysis Python
grouped = df.groupby([1])
Drag options to blanks, or click blank then click option'
A'Category'
B'Value'
C'Date'
D'Index'
Attempts:
3 left
💡 Hint
Common Mistakes
Using a column name that does not exist in the DataFrame.
Forgetting to put the column name inside quotes.
2fill in blank
medium

Complete the code to calculate the mean of each group after grouping by 'Category'.

Data Analysis Python
mean_values = df.groupby('Category').[1]()
Drag options to blanks, or click blank then click option'
Asum
Bmax
Ccount
Dmean
Attempts:
3 left
💡 Hint
Common Mistakes
Using sum() instead of mean().
Forgetting the parentheses after the function name.
3fill in blank
hard

Fix the error in the code to get the size of each group after grouping by 'Category'.

Data Analysis Python
group_sizes = df.groupby('Category').[1]
Drag options to blanks, or click blank then click option'
Asize()
Bsize
Ccount()
Dcount
Attempts:
3 left
💡 Hint
Common Mistakes
Using size without parentheses, which returns a method object.
Using count() which counts non-null values per column, not total rows.
4fill in blank
hard

Fill both blanks to create a dictionary with group names as keys and the sum of 'Value' as values.

Data Analysis Python
result = {group: data['Value'].[1]() for group, data in df.groupby([2])}
Drag options to blanks, or click blank then click option'
Asum
Bmean
C'Category'
D'Value'
Attempts:
3 left
💡 Hint
Common Mistakes
Using mean instead of sum for aggregation.
Grouping by the wrong column name.
5fill in blank
hard

Fill all three blanks to create a dictionary with group names as keys and the max 'Value' for each group.

Data Analysis Python
result = {group: data[[1]].[2]() for group, data in df.groupby([3])}
Drag options to blanks, or click blank then click option'
A'Value'
Bmax
C'Category'
D'Date'
Attempts:
3 left
💡 Hint
Common Mistakes
Using the wrong column name in the first blank.
Using min or mean instead of max.
Grouping by a column other than 'Category'.

Practice

(1/5)
1. What does the groupby() function do in pandas?
easy
A. It splits data into groups based on column values.
B. It sorts the data in ascending order.
C. It removes duplicate rows from the data.
D. It changes the data type of columns.

Solution

  1. Step 1: Understand the purpose of groupby()

    The groupby() function is used to split data into groups based on the values in one or more columns.
  2. Step 2: Compare with other options

    Sorting, removing duplicates, and changing data types are different operations and not the main function of groupby().
  3. Final Answer:

    It splits data into groups based on column values. -> Option A
  4. Quick Check:

    groupby() = split data by column [OK]
Hint: Remember: groupby splits data into groups by column values [OK]
Common Mistakes:
  • Confusing groupby with sorting or filtering
  • Thinking groupby changes data types
  • Assuming groupby removes duplicates
2. Which of the following is the correct syntax to group a DataFrame df by the column 'Category'?
easy
A. df.group_by('Category')
B. df.groupby('Category')
C. df.groupby['Category']
D. df.groupby(Category)

Solution

  1. Step 1: Recall correct method syntax

    The correct method name is groupby without underscore, called with parentheses and column name as a string.
  2. Step 2: Check each option

    The correct syntax is df.groupby('Category'). Incorrect versions include df.group_by('Category') (wrong method name), df.groupby['Category'] (wrong brackets), and df.groupby(Category) (missing quotes).
  3. Final Answer:

    df.groupby('Category') -> Option B
  4. Quick Check:

    Correct syntax uses parentheses and quotes [OK]
Hint: Use df.groupby('column_name') with quotes and parentheses [OK]
Common Mistakes:
  • Using underscore in groupby (group_by)
  • Using square brackets instead of parentheses
  • Not quoting the column name
3. Given the DataFrame df below, what is the output of df.groupby('Team')['Points'].sum()?
   Team  Points
0  A     10
1  B     15
2  A     5
3  B     10
4  C     7
medium
A. Team A 20 B 25 C 7 Name: Points, dtype: int64
B. Team A 10 B 15 C 7 Name: Points, dtype: int64
C. Team A 15 B 25 C 7 Name: Points, dtype: int64
D. Team A 5 B 10 C 7 Name: Points, dtype: int64

Solution

  1. Step 1: Group data by 'Team'

    The groups are: A with points 10 and 5, B with 15 and 10, C with 7.
  2. Step 2: Sum points in each group

    Sum for A = 10 + 5 = 15, for B = 15 + 10 = 25, for C = 7.
  3. Final Answer:

    Team A 15 B 25 C 7 Name: Points, dtype: int64 -> Option C
  4. Quick Check:

    Sum points per team = 15, 25, 7 [OK]
Hint: Add values in each group to get sum quickly [OK]
Common Mistakes:
  • Not summing all values per group
  • Mixing group labels and sums
  • Using count instead of sum
4. What is wrong with this code snippet?
grouped = df.groupby('Category')
result = grouped.sum['Sales']
print(result)
medium
A. Using square brackets instead of parentheses after sum.
B. Missing quotes around 'Category' in groupby.
C. Calling sum() without parentheses.
D. Using print() incorrectly.

Solution

  1. Step 1: Check method call syntax

    The sum function must be called with parentheses: sum(), not accessed with square brackets.
  2. Step 2: Verify other parts

    The groupby column is correctly quoted, and print usage is correct.
  3. Final Answer:

    Using square brackets instead of parentheses after sum. -> Option A
  4. Quick Check:

    sum() needs parentheses, not brackets [OK]
Hint: Call aggregation functions with parentheses like sum() [OK]
Common Mistakes:
  • Using brackets instead of parentheses for functions
  • Forgetting parentheses after sum
  • Misquoting column names
5. You have a DataFrame df with columns 'City', 'Category', and 'Sales'. How do you find the average sales for each city and category combination?
hard
A. df.groupby('City' & 'Category')['Sales'].mean()
B. df.groupby('City', 'Category')['Sales'].mean()
C. df.groupby('City' + 'Category')['Sales'].mean()
D. df.groupby(['City', 'Category'])['Sales'].mean()

Solution

  1. Step 1: Group by multiple columns

    To group by both 'City' and 'Category', pass a list of column names: ['City', 'Category'].
  2. Step 2: Calculate mean of 'Sales'

    After grouping, select 'Sales' column and apply mean() to get average sales per group.
  3. Final Answer:

    df.groupby(['City', 'Category'])['Sales'].mean() -> Option D
  4. Quick Check:

    Group by list of columns, then mean() [OK]
Hint: Group by list of columns: df.groupby(['col1','col2']) [OK]
Common Mistakes:
  • Passing multiple columns as separate arguments
  • Using bitwise AND (&) instead of list
  • Using string concatenation (+ ) instead of list
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard