Why NumPy is the numerical backbone in Data Analysis Python - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to import the NumPy library with its common alias.

Data Analysis Python

import [1] as np

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Apandas

Bnumpy

Cmatplotlib

Dscipy

Attempts:

3 left

💡 Hint

Common Mistakes

Using pandas instead of numpy.

Forgetting to use the alias np.

Importing matplotlib or scipy by mistake.

NumPy is imported using the name numpy. The common alias is np.

2fill in blank

medium

Complete the code to create a NumPy array from a Python list.

Data Analysis Python

arr = np.[1]([1, 2, 3, 4])

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Aarray

Blist

Cmatrix

Dseries

Attempts:

3 left

💡 Hint

Common Mistakes

Using list instead of array.

Trying to use series which is from pandas.

Using matrix which is different from array.

The function np.array() converts a Python list into a NumPy array.

3fill in blank

hard

Fix the error in the code to calculate the mean of a NumPy array.

Data Analysis Python

mean_value = arr.[1]()

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Amean

Baverage

Cmedian

Dmode

Attempts:

3 left

💡 Hint

Common Mistakes

Using average() as a method on the array.

Using median() which returns the middle value, not the mean.

Using mode() which is not a NumPy array method.

The correct method to calculate the average value of a NumPy array is mean().

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps each number to its square if the number is even.

Data Analysis Python

squares = {x: x[1]2 for x in range(1, 6) if x [2] 2 == 0}

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A**

B%

C//

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using + instead of exponentiation.

Using // which is floor division, not modulus.

Using == incorrectly without modulus.

The operator ** is used for exponentiation (square), and % checks if a number is even by remainder 0.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to the original words if the length is greater than 3.

Data Analysis Python

result = { [1]: [2] for word in words if len(word) [3] 3 }

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Aword.upper()

Bword

C>

Dlen(word)

Attempts:

3 left

💡 Hint

Common Mistakes

Using len(word) as the key instead of uppercase word.

Using < instead of > in the condition.

Swapping key and value positions.

The key is the uppercase word (word.upper()), the value is the original word (word), and the condition checks if length is greater than 3 (>).