Why DataFrame is the core data structure in Data Analysis Python - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a DataFrame from a dictionary.

Data Analysis Python

import pandas as pd
data = {'Name': ['Alice', 'Bob'], 'Age': [25, 30]}
df = pd.[1](data)
print(df)

Drag options to blanks, or click blank then click option'

ADataFrame

BSeries

Carray

Dlist

Attempts:

3 left

💡 Hint

Common Mistakes

Using Series instead of DataFrame

Trying to create DataFrame with list directly

The DataFrame constructor creates a table-like structure from a dictionary.

2fill in blank

medium

Complete the code to select the 'Age' column from the DataFrame.

Data Analysis Python

import pandas as pd
data = {'Name': ['Alice', 'Bob'], 'Age': [25, 30]}
df = pd.DataFrame(data)
age_column = df[1]['Age']
print(age_column)

Drag options to blanks, or click blank then click option'

A.at

B.loc

C[

D.iloc

Attempts:

3 left

💡 Hint

Common Mistakes

Using .iloc for label selection

Using .at which is for single values

Using square brackets [ ] selects a column by name from a DataFrame.

3fill in blank

hard

Fix the error in the code to filter rows where Age is greater than 25.

Data Analysis Python

import pandas as pd
data = {'Name': ['Alice', 'Bob', 'Charlie'], 'Age': [25, 30, 22]}
df = pd.DataFrame(data)
filtered = df[df['Age'] [1] 25]
print(filtered)

Drag options to blanks, or click blank then click option'

A>

B<

C==

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using < instead of >

Using == which checks equality

The operator > selects rows where Age is greater than 25.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps names to ages for people older than 23.

Data Analysis Python

data = {'Name': ['Alice', 'Bob', 'Charlie'], 'Age': [25, 30, 22]}
result = {data['Name'][i]: data['Age'][i] for i in range(len(data['Name'])) if data['Age'][i] [1] 23}
print(result)

Drag options to blanks, or click blank then click option'

A<

B>

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using < which selects ages less than 23

Using == which selects only age 23

The operator > filters ages greater than 23.

5fill in blank

hard

Fill all three blanks to create a DataFrame from a list of dictionaries and select rows where score is above 80.

Data Analysis Python

import pandas as pd
data = [{'name': 'Alice', 'score': 85}, {'name': 'Bob', 'score': 75}, {'name': 'Cara', 'score': 90}]
df = pd.[1](data)
high_scores = df[df['[2]'] [3] 80]
print(high_scores)

Drag options to blanks, or click blank then click option'

ADataFrame

Bscore

C>

DSeries

Attempts:

3 left

💡 Hint

Common Mistakes

Using Series instead of DataFrame

Selecting wrong column name

Using < instead of >

Use DataFrame to create the table, select the 'score' column, and filter with > to get scores above 80.

Practice

1. Why is a DataFrame considered the core data structure in pandas for data analysis?

easy

A. Because it is used to write data to files only.

B. Because it only stores data as a list of numbers without labels.

C. Because it is a type of graph used for visualization.

D. Because it organizes data in rows and columns like a table, making it easy to understand and use.

Solution

1. Step 1: Understand DataFrame structure

   A DataFrame organizes data in rows and columns, similar to a spreadsheet or table.

2. Step 2: Recognize its role in data analysis

   This tabular structure makes it easy to view, manipulate, and analyze data efficiently.

3. Final Answer:

   Because it organizes data in rows and columns like a table, making it easy to understand and use. -> Option D

4. Quick Check:

   DataFrame = tabular data structure [OK]

Hint: Think of DataFrame as a spreadsheet table for data [OK]

Common Mistakes:

• Confusing DataFrame with simple lists or arrays
• Thinking DataFrame is only for visualization
• Believing DataFrame stores data without labels

2. Which of the following is the correct way to create a simple DataFrame in pandas?

easy

A. pd.DataFrame({'Name': ['Alice', 'Bob'], 'Age': [25, 30]})

B. pd.DataFrame['Name', 'Age'] = ['Alice', 25]

C. pd.DataFrame(Name = 'Alice', Age = 25)

D. pd.DataFrame(['Alice', 25], ['Bob', 30])

Solution

1. Step 1: Check pandas DataFrame creation syntax

   The correct way is to pass a dictionary where keys are column names and values are lists of column data.

2. Step 2: Verify each option

   pd.DataFrame({'Name': ['Alice', 'Bob'], 'Age': [25, 30]}) uses a dictionary with lists, which is correct. Others have syntax errors or wrong formats.

3. Final Answer:

   pd.DataFrame({'Name': ['Alice', 'Bob'], 'Age': [25, 30]}) -> Option A

4. Quick Check:

   DataFrame creation = dictionary of lists [OK]

Hint: Use dictionary with column names as keys to create DataFrame [OK]

Common Mistakes:

• Using square brackets instead of parentheses for DataFrame
• Passing single values instead of lists for columns
• Incorrect assignment syntax

3. What will be the output of the following code?

import pandas as pd
data = {'City': ['NY', 'LA', 'SF'], 'Population': [8, 4, 3]}
df = pd.DataFrame(data)
print(df.loc[1, 'City'])

medium

A. NY

B. LA

C. SF

D. KeyError

Solution

1. Step 1: Understand DataFrame creation

   The DataFrame has rows indexed 0, 1, 2 with 'City' values 'NY', 'LA', 'SF' respectively.

2. Step 2: Access value at row 1, column 'City'

   Using df.loc[1, 'City'] accesses the second row's 'City' value, which is 'LA'.

3. Final Answer:

   LA -> Option B

4. Quick Check:

   Row 1 City = LA [OK]

Hint: loc[row, column] accesses exact cell by label [OK]

Common Mistakes:

• Confusing loc with iloc (integer position)
• Assuming index starts at 1 instead of 0
• Expecting KeyError due to wrong indexing

4. Identify the error in this code snippet that tries to create a DataFrame:

import pandas as pd
data = {'Name': ['Alice', 'Bob'], 'Age': 25}
df = pd.DataFrame(data)
print(df)

medium

A. The print statement syntax is incorrect.

B. DataFrame cannot be created without specifying columns explicitly.

C. Data dictionary values must be lists or arrays, not single values.

D. Pandas library is not imported correctly.

Solution

1. Step 1: Check data dictionary format

   The dictionary has a list for 'Name' and a single value for 'Age' instead of matching lists, which is invalid for DataFrame creation.

2. Step 2: Understand DataFrame input requirements

   DataFrame expects each column to have a list or array of values, even if only one row.

3. Final Answer:

   Data dictionary values must be lists or arrays, not single values. -> Option C

4. Quick Check:

   DataFrame columns need list values [OK]

Hint: Always use lists for column data when creating DataFrame [OK]

Common Mistakes:

• Passing single values instead of lists in data dictionary
• Assuming DataFrame can infer single values as rows
• Ignoring error messages about data format

5. You have a list of dictionaries representing sales data:

sales = [
  {'Product': 'A', 'Price': 10, 'Quantity': 2},
  {'Product': 'B', 'Price': 15, 'Quantity': 1},
  {'Product': 'A', 'Price': 10, 'Quantity': 3}
]

How can you create a DataFrame and then calculate the total sales amount for each product?

hard

A. Create DataFrame with pd.DataFrame(sales), then use df['Total'] = df['Price'] * df['Quantity'] and df.groupby('Product')['Total'].sum()

B. Create DataFrame with pd.DataFrame(sales), then use df.groupby('Product')['Price'].sum()

C. Create DataFrame with pd.DataFrame(sales), then use df.sum(axis=1) to get totals

D. Create DataFrame with pd.DataFrame(sales), then use df['Price'] * df['Quantity'] without grouping

Solution

1. Step 1: Create DataFrame from list of dictionaries

   Use pd.DataFrame(sales) to convert the list into a DataFrame with columns 'Product', 'Price', and 'Quantity'.

2. Step 2: Calculate total sales per row and group by product

   Create a new column 'Total' by multiplying 'Price' and 'Quantity'. Then group by 'Product' and sum the 'Total' values to get total sales per product.

3. Final Answer:

   Create DataFrame with pd.DataFrame(sales), then use df['Total'] = df['Price'] * df['Quantity'] and df.groupby('Product')['Total'].sum() -> Option A

4. Quick Check:

   Total sales = Price * Quantity grouped by Product [OK]

Hint: Multiply price and quantity first, then group by product [OK]

Common Mistakes:

• Summing price without considering quantity
• Not creating a total sales column before grouping
• Using sum(axis=1) which sums columns, not grouped totals