Series sorting in Data Analysis Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to sort the Series in ascending order.

Data Analysis Python

import pandas as pd
s = pd.Series([3, 1, 2])
s_sorted = s.[1]()

Drag options to blanks, or click blank then click option'

Asorted

Bsort_index

Csort

Dsort_values

Attempts:

3 left

💡 Hint

Common Mistakes

Using sort_index() which sorts by index, not values.

Using sorted() which returns a list, not a Series.

The sort_values() method sorts the Series by its values in ascending order.

2fill in blank

medium

Complete the code to sort the Series in descending order.

Data Analysis Python

import pandas as pd
s = pd.Series([3, 1, 2])
s_sorted_desc = s.sort_values([1]=False)

Drag options to blanks, or click blank then click option'

Areverse

Bdescending

Cascending

Dorder

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'descending' which is not a valid parameter.

Using 'reverse' which is not a parameter for sort_values.

The ascending parameter controls the sort order. Setting it to True sorts ascending, False sorts descending.

3fill in blank

hard

Fix the error in the code to sort the Series by index.

Data Analysis Python

import pandas as pd
s = pd.Series([3, 1, 2], index=['b', 'a', 'c'])
s_sorted = s.[1]()

Drag options to blanks, or click blank then click option'

Asort_values

Bsort_index

Csort

Dsorted

Attempts:

3 left

💡 Hint

Common Mistakes

Using sort_values() which sorts by values, not index.

Using sorted() which returns a list, not a Series.

The sort_index() method sorts the Series by its index labels.

4fill in blank

hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 letters.

Data Analysis Python

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' which filters shorter words.

Using 'word' instead of 'len(word)' for the value.

We use len(word) to get the length, and filter words with length greater than 3 using >.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than 1.

Data Analysis Python

data = {'a': 1, 'b': 2, 'c': 3}
result = { [1]: [2] for k, v in data.items() if v [3] 1 }

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'k' instead of 'k.upper()' for keys.

Using '<' instead of '>' for filtering values.

Keys are converted to uppercase with k.upper(). Values are kept as v. We filter values greater than 1 using >.

Practice

1. What does the sort_values() method do when applied to a pandas Series?

easy

A. Sorts the Series by its data values in ascending order by default.

B. Sorts the Series by its index labels in ascending order by default.

C. Removes duplicate values from the Series.

D. Converts the Series into a DataFrame.

Solution

1. Step 1: Understand the purpose of sort_values()

   This method sorts the Series based on the data values it contains, not the index labels.

2. Step 2: Default sorting order

   By default, sort_values() sorts in ascending order, meaning smallest to largest values.

3. Final Answer:

   Sorts the Series by its data values in ascending order by default. -> Option A

4. Quick Check:

   sort_values() sorts by values = D [OK]

Hint: Remember: sort_values() sorts by data values, not index [OK]

Common Mistakes:

• Confusing sort_values() with sort_index()
• Thinking it sorts by index labels
• Assuming it removes duplicates

2. Which of the following is the correct syntax to sort a pandas Series named data by its index labels in descending order?

easy

A. data.sort_index(ascending=False)

B. data.sort_values(ascending=False)

C. data.sort(ascending=False)

D. data.sort_by_index(desc=True)

Solution

1. Step 1: Identify method for sorting by index

   To sort by index labels, use sort_index(), not sort_values().

2. Step 2: Apply descending order

   The parameter ascending=False sorts in descending order.

3. Final Answer:

   data.sort_index(ascending=False) -> Option A

4. Quick Check:

   sort_index() + ascending=False = B [OK]

Hint: Use sort_index() to sort by index, add ascending=False for descending [OK]

Common Mistakes:

• Using sort_values() instead of sort_index()
• Using non-existent methods like sort_by_index()
• Missing the ascending parameter

3. Given the following pandas Series:

import pandas as pd
s = pd.Series([30, 10, 20], index=['c', 'a', 'b'])
print(s.sort_values())

What will be the output?

medium

A. a 10
c 30
b 20
dtype: int64

B. c 30
b 20
a 10
dtype: int64

C. a 10
b 20
c 30
dtype: int64

D. b 20
a 10
c 30
dtype: int64

Solution

1. Step 1: Understand the Series and sort_values()

   The Series has values [30, 10, 20] with indexes ['c', 'a', 'b']. Sorting by values arranges them as 10, 20, 30.

2. Step 2: Match sorted values with their indexes

   Value 10 corresponds to index 'a', 20 to 'b', and 30 to 'c'. So sorted Series is:
   a 10
   b 20
   c 30

3. Final Answer:

   a 10 b 20 c 30 dtype: int64 -> Option C

4. Quick Check:

   sort_values() sorts values ascending = A [OK]

Hint: Match sorted values with their original indexes carefully [OK]

Common Mistakes:

• Sorting by index instead of values
• Mixing up index labels with values
• Assuming default sort is descending

4. What is wrong with the following code snippet if the goal is to sort a pandas Series s by its index in ascending order?

sorted_s = s.sort_values(ascending=True)

medium

A. The ascending parameter should be False to sort ascending.

B. It sorts by values, not by index, so index order is not guaranteed.

C. The method sort_values() does not exist for Series.

D. The code will raise a syntax error.

Solution

1. Step 1: Identify the method used

   The code uses sort_values() which sorts by data values, not index labels.

2. Step 2: Understand the goal

   The goal is to sort by index ascending, so sort_index() should be used instead.

3. Final Answer:

   It sorts by values, not by index, so index order is not guaranteed. -> Option B

4. Quick Check:

   sort_values() sorts values, not index = C [OK]

Hint: Use sort_index() to sort by index, not sort_values() [OK]

Common Mistakes:

• Confusing sort_values() with sort_index()
• Thinking ascending=False sorts ascending
• Expecting syntax error when none occurs

5. You have a pandas Series sales with product codes as index and sales numbers as values:

product_codes = ['p3', 'p1', 'p2', 'p4']
sales_numbers = [200, 450, 300, 150]
sales = pd.Series(sales_numbers, index=product_codes)

How do you sort this Series so that the products are ordered by their codes alphabetically, but the sales numbers remain correctly matched?

hard

A. sales.sort_index(ascending=False)

B. sales.sort_values()

C. sales.sort_values(ascending=False)

D. sales.sort_index()

Solution

1. Step 1: Understand the data and goal

   The Series has product codes as index and sales numbers as values. Sorting by product codes means sorting by index labels.

2. Step 2: Choose correct sorting method

   Use sort_index() to sort by index labels alphabetically, preserving the correct sales numbers with their products.

3. Final Answer:

   sales.sort_index() -> Option D

4. Quick Check:

   Sort by index to order products alphabetically = A [OK]

Hint: Sort by index to reorder labels, not by values [OK]

Common Mistakes:

• Using sort_values() which sorts by sales numbers
• Sorting descending when ascending is needed
• Mixing up index and values sorting