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Data Analysis Pythondata~10 mins

Series indexing and selection in Data Analysis Python - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to select the element at index 2 from the Series.

Data Analysis Python
import pandas as pd
s = pd.Series([10, 20, 30, 40])
value = s[1]
Drag options to blanks, or click blank then click option'
A[2]
B.loc[2]
C.iloc[2]
D[3]
Attempts:
3 left
💡 Hint
Common Mistakes
Using .loc instead of square brackets for positional selection
Using the wrong index number
2fill in blank
medium

Complete the code to select elements with labels 1 and 3 using .loc.

Data Analysis Python
import pandas as pd
s = pd.Series([100, 200, 300, 400], index=[0, 1, 2, 3])
subset = s[1]
Drag options to blanks, or click blank then click option'
A[[1, 3]]
B.loc[[1, 3]]
C.iloc[[1, 3]]
D[1, 3]
Attempts:
3 left
💡 Hint
Common Mistakes
Using .iloc instead of .loc for label-based selection
Not using double brackets for list selection
3fill in blank
hard

Fix the error in the code to select the element at position 1 using .iloc.

Data Analysis Python
import pandas as pd
s = pd.Series([5, 10, 15])
value = s[1]
Drag options to blanks, or click blank then click option'
A.iloc[1]
B.loc[1]
C[1]
D[[1]]
Attempts:
3 left
💡 Hint
Common Mistakes
Using .loc instead of .iloc for position selection
Using double brackets which returns a Series instead of a scalar
4fill in blank
hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 characters.

Data Analysis Python
words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if [2]
Drag options to blanks, or click blank then click option'
Alen(word)
Blen(word) > 3
Cword
Dlen(word) < 3
Attempts:
3 left
💡 Hint
Common Mistakes
Using the word itself instead of its length
Using the wrong condition for filtering
5fill in blank
hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than 0.

Data Analysis Python
data = {'a': 1, 'b': -2, 'c': 3}
result = [1]: [2] for k, v in data.items() if v [3] 0}
Drag options to blanks, or click blank then click option'
Ak.upper()
Bv
C>
Dk.lower()
Attempts:
3 left
💡 Hint
Common Mistakes
Using k.lower() instead of k.upper()
Using '<' instead of '>' in the condition
Using keys or values incorrectly in the comprehension

Practice

(1/5)
1. What does series['a'] do in a pandas Series with index labels?
easy
A. Returns a slice from start to label 'a'
B. Selects the value at label 'a' in the Series
C. Selects the value at position 0 in the Series
D. Raises an error because 'a' is not a position

Solution

  1. Step 1: Understand label-based indexing

    Using series['a'] accesses the value at the index label 'a', not position.
  2. Step 2: Differentiate label vs position

    Label 'a' is a named index, so it returns the value at that label.
  3. Final Answer:

    Selects the value at label 'a' in the Series -> Option B
  4. Quick Check:

    Label indexing = value at label [OK]
Hint: Use labels inside quotes to get values by label [OK]
Common Mistakes:
  • Confusing label with position indexing
  • Thinking 'a' is a position index
  • Expecting a slice instead of single value
2. Which of these is the correct syntax to select multiple labels 'a' and 'c' from a Series named ser?
easy
A. ser.loc[['a', 'c']]
B. ser['a', 'c']
C. ser.loc['a', 'c']
D. ser.iloc[['a', 'c']]

Solution

  1. Step 1: Understand selection of multiple labels

    To select multiple labels, use loc with a list of labels inside double brackets.
  2. Step 2: Check syntax correctness

    ser.loc[['a', 'c']] is correct; distractors B and C use tuples (KeyError), D uses iloc which expects positions (TypeError).
  3. Final Answer:

    ser.loc[['a', 'c']] -> Option A
  4. Quick Check:

    Use loc with list for multiple labels [OK]
Hint: Use ser.loc[[labels]] to select multiple labels [OK]
Common Mistakes:
  • Using single brackets for multiple labels
  • Omitting loc when selecting multiple labels
  • Passing labels as separate arguments instead of a list
3. Given the Series:
import pandas as pd
ser = pd.Series([10, 20, 30, 40], index=['a', 'b', 'c', 'd'])
print(ser['b':'d'])

What is the output?
medium
A. b 20 c 30 d 40 dtype: int64
B. b 20 c 30 dtype: int64
C. 20 30 40
D. 20 30

Solution

  1. Step 1: Understand label slicing in Series

    Label slicing with ser['b':'d'] includes both start and end labels.
  2. Step 2: Identify values for labels 'b' to 'd'

    Labels 'b', 'c', and 'd' correspond to values 20, 30, and 40 respectively.
  3. Final Answer:

    b 20 c 30 d 40 dtype: int64 -> Option A
  4. Quick Check:

    Label slice includes end label [OK]
Hint: Label slices include the end label [OK]
Common Mistakes:
  • Excluding the end label in slice
  • Confusing label slicing with position slicing
  • Expecting only values without index labels
4. What is wrong with this code snippet?
import pandas as pd
ser = pd.Series([1, 2, 3], index=['x', 'y', 'z'])
print(ser[1:2])

Why might this cause confusion?
medium
A. It raises a KeyError because 1 and 3 are not labels
B. It returns a single value instead of a slice
C. It returns values for labels 'y' and 'z' inclusive
D. It slices by position, excluding index label 'z'

Solution

  1. Step 1: Understand position slicing in Series

    Using ser[1:2] slices by position, not label, and excludes the end position.
  2. Step 2: Identify slice range and output

    Position 1 (inclusive) to 2 (exclusive) corresponds to label 'y' (position 1), excluding position 2 ('z').
  3. Final Answer:

    It slices by position, excluding index label 'z' -> Option D
  4. Quick Check:

    Position slices exclude end position [OK]
Hint: Position slices exclude the end index [OK]
Common Mistakes:
  • Expecting label slicing with integer slice
  • Thinking slice includes end position
  • Confusing KeyError with slicing behavior
5. You have a Series ser with index labels ['a', 'b', 'c', 'd', 'e'] and values [5, 10, 15, 20, 25]. How do you select all values greater than 10 using Series indexing and selection?
hard
A. ser[ser.index > 10]
B. ser.index[ser > 10]
C. ser[ser > 10]
D. ser.loc[ser.index > 10]

Solution

  1. Step 1: Use boolean indexing on Series values

    Comparing ser > 10 creates a boolean mask for values greater than 10.
  2. Step 2: Apply boolean mask to Series

    Using ser[ser > 10] selects values where the mask is True.
  3. Final Answer:

    ser[ser > 10] -> Option C
  4. Quick Check:

    Boolean mask on values selects correct subset [OK]
Hint: Use ser[ser > value] to filter by value condition [OK]
Common Mistakes:
  • Trying to filter by index values instead of data values
  • Using loc with boolean mask on index instead of values
  • Confusing index labels with values in condition
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10 questions~5 mineasy hard