Reshaping and transposing in Data Analysis Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to reshape the array into 2 rows and 3 columns.

Data Analysis Python

import numpy as np
arr = np.array([1, 2, 3, 4, 5, 6])
reshaped = arr.[1]((2, 3))
print(reshaped)

Drag options to blanks, or click blank then click option'

Atranspose

Bresize

Cflatten

Dreshape

Attempts:

3 left

💡 Hint

Common Mistakes

Using flatten instead of reshape.

Using transpose which only swaps axes.

The reshape method changes the shape of the array without changing its data.

2fill in blank

medium

Complete the code to transpose the 2D array.

Data Analysis Python

import numpy as np
arr = np.array([[1, 2, 3], [4, 5, 6]])
transposed = arr.[1]()
print(transposed)

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Atranspose

BT

Creshape

Dflatten

Attempts:

3 left

💡 Hint

Common Mistakes

Using reshape instead of transpose.

Using T without parentheses (T is an attribute, not a method).

The transpose() method swaps the rows and columns of the array.

3fill in blank

hard

Fix the error in reshaping the array to 3 rows and 2 columns.

Data Analysis Python

import numpy as np
arr = np.array([1, 2, 3, 4, 5])
reshaped = np.[1](arr, (3, 2))
print(reshaped)

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Aflatten

Bresize

Creshape

Dtranspose

Attempts:

3 left

💡 Hint

Common Mistakes

Using reshape which causes an error due to size mismatch.

Using transpose which does not change shape like this.

The resize method can change the size of the array and fill with repeated values if needed, allowing reshaping incompatible with original size.

4fill in blank

hard

Fill both blanks to create a dictionary with word lengths for words longer than 3 characters.

Data Analysis Python

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if len(word) [2] 3}
print(lengths)

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Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using < instead of > in the condition.

Using the word itself instead of its length.

The dictionary comprehension uses len(word) to get length and filters words with length greater than 3 using >.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than 0.

Data Analysis Python

data = {'a': 1, 'b': -2, 'c': 3}
result = {{ [1]: [2] for k, v in data.items() if v [3] 0 }}
print(result)

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Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using original keys instead of uppercase.

Using < instead of > in the condition.

The dictionary comprehension uses k.upper() for keys, v for values, and filters values greater than 0 with >.