Broadcasting rules in Data Analysis Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to add a 1D array to each row of a 2D array using broadcasting.

Data Analysis Python

import numpy as np
arr2d = np.array([[1, 2, 3], [4, 5, 6]])
arr1d = np.array([10, 20, 30])
result = arr2d + [1]
print(result)

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Anp.array([1, 2])

Barr2d

Carr1d

Dnp.array([[10], [20], [30]])

Attempts:

3 left

💡 Hint

Common Mistakes

Using arr2d instead of arr1d causes no change.

Using arrays with incompatible shapes causes errors.

Adding a 1D array to a 2D array adds the 1D array to each row by broadcasting.

2fill in blank

medium

Complete the code to multiply a 2D array by a column vector using broadcasting.

Data Analysis Python

import numpy as np
arr2d = np.array([[1, 2], [3, 4], [5, 6]])
col_vec = np.array([[10], [20], [30]])
result = arr2d * [1]
print(result)

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Acol_vec

Barr2d

Cnp.array([10, 20, 30])

Dnp.array([[1, 2, 3]])

Attempts:

3 left

💡 Hint

Common Mistakes

Using a 1D array with shape (3,) instead of (3,1) causes shape mismatch.

Multiplying by arr2d itself does not change the array.

Multiplying by a column vector broadcasts the vector across columns of the 2D array.

3fill in blank

hard

Fix the error in the code to add a 1D array to a 2D array when shapes are incompatible.

Data Analysis Python

import numpy as np
arr2d = np.array([[1, 2, 3], [4, 5, 6]])
arr1d = np.array([10, 20])
result = arr2d + [1]
print(result)

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Aarr1d

Barr1d.reshape(2, 1)

Carr1d.reshape(3, 1)

Darr1d.reshape(1, 2)

Attempts:

3 left

💡 Hint

Common Mistakes

Adding arr1d directly causes a shape mismatch error.

Reshaping to (1,2) does not match arr2d's shape.

Reshaping arr1d to (2,1) allows broadcasting to add it to arr2d with shape (2,3).

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if length is greater than 3.

Data Analysis Python

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if [2] > 3}
print(lengths)

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Alen(word)

Bword

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of len(word) for the value.

Checking word > 3 instead of len(word) > 3.

The dictionary maps each word to its length if the length is greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths only if length is greater than 3.

Data Analysis Python

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {{ [1]: [2] for word in words if [3] > 3 }}
print(lengths)

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Aword.upper()

Blen(word)

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Not converting words to uppercase for the key.

Using word instead of len(word) for the value or condition.

The dictionary maps each uppercase word to its length if the length is greater than 3.