Boolean indexing in Data Analysis Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to select rows where the 'age' column is greater than 30.

Data Analysis Python

filtered = df[df['age'] [1] 30]

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A<

B>

C==

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' will select wrong rows.

Using '==' will select only rows where age equals 30.

We use the '>' operator to select rows where 'age' is greater than 30.

2fill in blank

medium

Complete the code to select rows where the 'score' column is equal to 100.

Data Analysis Python

perfect_scores = df[df['score'] [1] 100]

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A!=

B>=

C<

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' instead of '==' causes syntax errors.

Using '!=' selects rows where score is not 100.

The '==' operator checks for equality, so it selects rows where 'score' is exactly 100.

3fill in blank

hard

Fix the error in the code to select rows where 'height' is less than or equal to 170.

Data Analysis Python

short_people = df[df['height'] [1] 170]

Drag options to blanks, or click blank then click option'

A<=

B<

C=>

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=>' is invalid syntax.

Using '<' excludes values equal to 170.

The correct operator for 'less than or equal to' is '<='.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if the length is greater than 3.

Data Analysis Python

{word: [1] for word in words if [2]

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Alen(word)

Bword

Clen(word) > 3

Dword > 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'word' as value instead of length.

Using 'word > 3' which compares string to number.

The dictionary maps each word to its length (len(word)) only if the length is greater than 3 (len(word) > 3).

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their scores only if the score is greater than 50.

Data Analysis Python

{ [1]: [2] for word, score in data.items() if [3] }

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Aword.upper()

Bscore

Cscore > 50

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.lower() instead of word.upper().

Not filtering scores correctly.

The dictionary keys are uppercase words (word.upper()), values are scores, and only scores greater than 50 are included.