cy.intercept() for request interception in Cypress - Test Execution Trace

Test Overview

This test uses cy.intercept() to intercept a network request and verify that the intercepted response contains the expected data.

Test Code - Cypress

Cypress

describe('API request interception test', () => {
  it('intercepts GET /api/users and checks response', () => {
    cy.intercept('GET', '/api/users', {
      statusCode: 200,
      body: { users: [{ id: 1, name: 'Alice' }] }
    }).as('getUsers');

    cy.visit('/users');

    cy.wait('@getUsers').its('response.statusCode').should('eq', 200);
    cy.get('#user-list').should('contain.text', 'Alice');
  });
});

Execution Trace - 4 Steps

Step	Action	System State	Assertion	Result
1	cy.intercept() is set up to intercept GET requests to /api/users and respond with a mocked user list	Test runner is ready, intercept is active	—	PASS
2	cy.visit('/users') navigates the browser to the users page	Browser loads the /users page, triggering the GET /api/users request	—	PASS
3	cy.wait('@getUsers') waits for the intercepted GET /api/users request to complete	Intercepted request completes with mocked response	Check that response status code equals 200	PASS
4	cy.get('#user-list') finds the user list element and checks it contains text 'Alice'	User list element is visible on the page with mocked user data	Verify that user list contains 'Alice'	PASS

Failure Scenario

Failing Condition: The intercepted request does not return the mocked response or the page does not render the user list correctly

Execution Trace Quiz - 3 Questions

What does cy.intercept() do in this test?

A Intercepts the GET /api/users request and returns a mocked response

B Clicks a button on the page

C Navigates to the /users page

D Checks the text inside an element

Key Result

Use cy.intercept() to control and test network requests by mocking responses, which helps isolate frontend behavior from backend dependencies.

Practice

1. What is the main purpose of cy.intercept() in Cypress testing?

easy

A. To watch or modify network requests during tests

B. To create UI elements dynamically

C. To run tests in parallel

D. To generate random test data

Solution

1. Step 1: Understand the role of cy.intercept()

   This command is used to observe or change network requests made by the app during testing.

2. Step 2: Compare with other options

   The other options describe unrelated testing tasks: creating UI elements dynamically, running tests in parallel, or generating random test data.

3. Final Answer:

   To watch or modify network requests during tests -> Option A

4. Quick Check:

   cy.intercept() = watch or modify requests [OK]

Hint: Remember: intercept means catch or change requests [OK]

Common Mistakes:

• Confusing cy.intercept() with UI commands
• Thinking it runs tests in parallel
• Assuming it generates test data

2. Which of the following is the correct syntax to intercept a GET request to '/api/users' and stub a response with status 200?

easy

A. cy.intercept('GET', '/api/users', 200)

B. cy.intercept('/api/users', 'GET', { statusCode: 200 })

C. cy.intercept('POST', '/api/users', { status: 200 })

D. cy.intercept('GET', '/api/users', { statusCode: 200, body: [] })

Solution

1. Step 1: Check correct parameter order and object structure

   The correct order is method, URL, then response object with statusCode and body.

2. Step 2: Validate each option

   cy.intercept('GET', '/api/users', { statusCode: 200, body: [] }) matches correct syntax. cy.intercept('/api/users', 'GET', { statusCode: 200 }) swaps method and URL. cy.intercept('POST', '/api/users', { status: 200 }) uses wrong method and missing body. cy.intercept('GET', '/api/users', 200) passes status as number, not object.

3. Final Answer:

   cy.intercept('GET', '/api/users', { statusCode: 200, body: [] }) -> Option D

4. Quick Check:

   Method, URL, response object = cy.intercept('GET', '/api/users', { statusCode: 200, body: [] }) [OK]

Hint: Method first, then URL, then response object [OK]

Common Mistakes:

• Swapping method and URL parameters
• Using status instead of statusCode
• Passing status as a number alone

3. Given this code snippet, what will be the output of the intercepted request's status code?

cy.intercept('GET', '/api/data', { statusCode: 404, body: { error: 'Not found' } }).as('getData')
cy.visit('/data-page')
cy.wait('@getData').then(({ response }) => {
  console.log(response.statusCode)
})

medium

A. 404

B. 200

C. undefined

D. 500

Solution

1. Step 1: Analyze the intercept stub response

   The intercept stubs the GET request to '/api/data' with statusCode 404 and error message.

2. Step 2: Understand the console log output

   The cy.wait waits for the intercepted request. The response object uses response.status (which is 404), but the code logs response.statusCode, which is undefined.

3. Final Answer:

   undefined -> Option C

4. Quick Check:

   response.statusCode = undefined (use response.status) [OK]

Hint: cy.wait response uses .status, not .statusCode [OK]

Common Mistakes:

• Logging response.statusCode instead of response.status
• Confusing response.status with statusCode
• Expecting default 200 without stub

4. Identify the error in this Cypress intercept code:

cy.intercept('GET', '/api/items', (req) => {
  req.reply({ status: 201, body: { id: 1 } })
})

medium

A. Callback function should return a value

B. Using 'status' instead of 'statusCode' in reply object

C. Incorrect URL format

D. Missing method parameter in intercept

Solution

1. Step 1: Check the reply object keys

   The reply object must use 'statusCode' to set HTTP status, not 'status'.

2. Step 2: Verify other parts

   Method and URL are correct, and callback does not need to return a value.

3. Final Answer:

   Using 'status' instead of 'statusCode' in reply object -> Option B

4. Quick Check:

   Use statusCode, not status [OK]

Hint: Use statusCode key in reply, not status [OK]

Common Mistakes:

• Confusing status with statusCode
• Thinking callback must return a value
• Assuming URL format is wrong

5. You want to test how your app handles a slow server response for a POST request to '/api/login'. Which cy.intercept() usage correctly simulates a 2-second delay with a 200 status and a JSON body { success: true }?

hard

A. cy.intercept('POST', '/api/login', { delay: 2000, statusCode: 200, body: { success: true } })

B. cy.intercept('POST', '/api/login', { delayMs: 2000, status: 200, body: { success: true } })

C. cy.intercept('POST', '/api/login', (req) => { req.reply({ delay: 2000, status: 200, body: { success: true } }) })

D. cy.intercept('POST', '/api/login', (req) => { req.delay(2000).reply({ statusCode: 200, body: { success: true } }) })

Solution

1. Step 1: Understand delay usage in cy.intercept

   Delay, statusCode, and body can be used directly in the response object without a callback.

2. Step 2: Check each option's correctness

   cy.intercept('POST', '/api/login', { delay: 2000, statusCode: 200, body: { success: true } }) correctly uses delay, statusCode, and body directly. cy.intercept('POST', '/api/login', { delayMs: 2000, status: 200, body: { success: true } }) uses wrong keys 'delayMs' and 'status'. cy.intercept('POST', '/api/login', (req) => { req.reply({ delay: 2000, status: 200, body: { success: true } }) }) uses callback but 'status' instead of 'statusCode'. cy.intercept('POST', '/api/login', (req) => { req.delay(2000).reply({ statusCode: 200, body: { success: true } }) }) tries chaining a non-existent req.delay method.

3. Final Answer:

   cy.intercept('POST', '/api/login', { delay: 2000, statusCode: 200, body: { success: true } }) -> Option A

4. Quick Check:

   Direct { delay, statusCode, body } [OK]

Hint: Delay works directly in response object [OK]

Common Mistakes:

• Using wrong keys like delayMs or status
• Using status instead of statusCode in callback
• Trying to chain non-existent req.delay method