[Solved] What will be the output of this C# code?class Base { public virtual string GetName() => "Base"; } class Derived : Base { public override string GetName() => "Derived";... | C Sharp (C#)

C Sharp (C#) - Polymorphism and Abstract Classes

What will be the output of this C# code?

class Base { public virtual string GetName() => "Base"; } class Derived : Base { public override string GetName() => "Derived"; } class Program { static void Main() { Base obj = new Derived(); Console.WriteLine(obj.GetName()); } }

ACompilation error

BBase

CDerived

DRuntime error

Step-by-Step Solution

Solution:

Step 1: Understand object type and method call
Variable obj is of type Base but holds a Derived object. The method GetName is virtual and overridden in Derived.
Step 2: Determine which method runs at runtime
Because of runtime polymorphism, the overridden method in Derived is called, printing "Derived".
Final Answer:
Derived -> Option C
Quick Check:
Virtual method call = Derived method runs [OK]

Quick Trick: Virtual method calls use actual object type at runtime [OK]

Common Mistakes:

MISTAKES

Assuming method from variable type runs
Expecting compile-time method binding
Confusing compilation and runtime errors

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What will be the output of this C# code?

Step 1: Understand object type and method call

Step 2: Determine which method runs at runtime

Final Answer:

Quick Check:

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