[Solved] What will be the output of this C# code?try { Console.WriteLine("Start"); int x = 5 / 0; Console.WriteLine("End"); } catch (DivideByZeroException) { Console.WriteLine("Error caught"); } | C Sharp (C#)

C Sharp (C#) - Exception Handling

What will be the output of this C# code?

try {
    Console.WriteLine("Start");
    int x = 5 / 0;
    Console.WriteLine("End");
} catch (DivideByZeroException) {
    Console.WriteLine("Error caught");
}

AStart\nError caught

BError caught

CStart\nEnd

DStart

Step-by-Step Solution

Solution:

Step 1: Trace code inside try block
"Start" prints first. Then division by zero causes an exception.
Step 2: Exception triggers catch block
Catch block runs and prints "Error caught". The line after division is skipped.
Final Answer:
Start\nError caught -> Option A
Quick Check:
Exception skips rest of try, catch prints message [OK]

Quick Trick: Exception skips rest of try, catch runs next [OK]

Common Mistakes:

MISTAKES

Assuming 'End' prints after exception
Thinking catch runs before 'Start'
Ignoring exception and continuing try

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What will be the output of this C# code?

Step 1: Trace code inside try block

Step 2: Exception triggers catch block

Final Answer:

Quick Check:

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