Solution:Step 1: Trace Speak() calls through inheritancePuppy.Speak() calls base.Speak() which is Dog.Speak(), which calls base.Speak() (Animal.Speak()).Step 2: Combine returned stringsAnimal.Speak() returns "Animal sound"; Dog adds " and Bark"; Puppy adds " and Whine".Final Answer:"Animal sound and

[Solved] Given these classes:class Animal { public virtual string Speak() => "Animal sound"; } class Dog : Animal { public override string Speak() => base.... }What is the output of new Puppy().Speak()? | C Sharp (C#)

C Sharp (C#) - Inheritance

Given these classes:

class Animal {
    public virtual string Speak() => "Animal sound";
}
class Dog : Animal {
    public override string Speak() => base.Speak() + " and Bark";
}
class Puppy : Dog {
    public override string Speak() => base.Speak() + " and Whine";
}

What is the output of new Puppy().Speak()?

A"Animal sound and Bark and Whine"

B"Animal sound and Whine"

C"Animal sound and Bark"

D"Whine and Bark and Animal sound"

Step-by-Step Solution

Solution:

Step 1: Trace Speak() calls through inheritance
Puppy.Speak() calls base.Speak() which is Dog.Speak(), which calls base.Speak() (Animal.Speak()).
Step 2: Combine returned strings
Animal.Speak() returns "Animal sound"; Dog adds " and Bark"; Puppy adds " and Whine".
Final Answer:
"Animal sound and Bark and Whine" -> Option A
Quick Check:
base chains calls up inheritance [OK]

Quick Trick: base calls chain up inheritance returning combined results [OK]

Common Mistakes:

MISTAKES

Ignoring base call chaining
Assuming only Puppy or Dog Speak runs
Mixing order of concatenation

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More C Sharp (C#) Quizzes

Given these classes:

Step 1: Trace Speak() calls through inheritance

Step 2: Combine returned strings

Final Answer:

Quick Check:

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