[Solved] What will be the output of the following C# code?try { throw new Exception("Error 1"); } catch (Exception ex) { Console.WriteLine(ex.Message); throw; } | C Sharp (C#)

C Sharp (C#) - Exception Handling

What will be the output of the following C# code?

try {
  throw new Exception("Error 1");
} catch (Exception ex) {
  Console.WriteLine(ex.Message);
  throw;
}

AError 1 printed, then program terminates with the same exception.

BNo output, program silently terminates.

CError 1 printed, then program continues normally.

DCompilation error due to missing catch block.

Step-by-Step Solution

Solution:

Step 1: Analyze the try block
The try block throws an exception with message "Error 1".
Step 2: Analyze the catch block
The catch block prints the exception message, then rethrows the same exception using throw;.
Step 3: Understand program flow after rethrow
Since the exception is rethrown and not caught again, the program terminates with the same exception after printing.
Final Answer:
Error 1 printed, then program terminates with the same exception. -> Option A
Quick Check:
Print then rethrow = B [OK]

Quick Trick: Rethrow after print causes termination with printed message [OK]

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