TryParse for safe conversion in C Sharp (C#) - Mini Project: Build & Apply

TryParse for safe conversion

📖 Scenario: You are building a simple program that reads user input as text and tries to convert it safely into a number. This is common when users type numbers but might make mistakes.

🎯 Goal: Create a program that uses int.TryParse to safely convert a string to an integer without crashing. If the conversion works, show the number; if not, show a friendly error message.

📋 What You'll Learn

Create a string variable called input with the exact value "123".

Create a variable called number to store the converted integer.

Use int.TryParse with input and out number to try converting the string.

Use an if statement to check if conversion succeeded.

Print "Conversion succeeded: {number}" if true, else print "Conversion failed".

💡 Why This Matters

🌍 Real World

User input from keyboards or files often comes as text. Using TryParse helps programs handle invalid input gracefully without crashing.

💼 Career

Many software jobs require validating and converting user input safely. Knowing TryParse is essential for building robust applications.

1

DATA SETUP: Create the input string

Create a string variable called input and set it to the exact value "123".

C Sharp (C#)

# Your code here

Need a hint?

Use string input = "123"; to create the input text.

2

CONFIGURATION: Declare the integer variable

Create an integer variable called number to store the converted value.

C Sharp (C#)

string input = "123";
# Your code here

Need a hint?

Declare int number; without assigning a value yet.

3

CORE LOGIC: Use TryParse to convert safely

Use int.TryParse with input and out number inside an if statement to check if conversion succeeds.

C Sharp (C#)

string input = "123";
int number;
# Your code here

Need a hint?

Use if (int.TryParse(input, out number)) to check conversion.

4

OUTPUT: Print the conversion result

Inside the if block, write Console.WriteLine($"Conversion succeeded: {number}");. Inside the else block, write Console.WriteLine("Conversion failed"); to show the result.

C Sharp (C#)

string input = "123";
int number;
if (int.TryParse(input, out number))
{
    // Your code here
}
else
{
    // Your code here
}

Need a hint?

Use Console.WriteLine to print the success or failure message.