Ternary conditional operator in C Sharp (C#) - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to assign the smaller number to min using the ternary operator.

C Sharp (C#)

int a = 5;
int b = 10;
int min = (a < b) ? [1] : b;

Drag options to blanks, or click blank then click option'

A5

Ba

Cb

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Using b instead of a for the true part.

Putting the condition inside the blank.

The ternary operator checks if a < b. If true, it assigns a to min, otherwise b.

2fill in blank

medium

Complete the code to assign result as "Even" or "Odd" based on num.

C Sharp (C#)

int num = 7;
string result = (num % 2 == 0) ? [1] : "Odd";

Drag options to blanks, or click blank then click option'

A"Even"

B"Odd"

Cnum

D"Number"

Attempts:

3 left

💡 Hint

Common Mistakes

Assigning "Odd" for the true part.

Using num instead of a string.

The ternary operator checks if num is even. If true, it assigns "Even", else "Odd".

3fill in blank

hard

Fix the error in the ternary operator to assign status correctly.

C Sharp (C#)

int score = 85;
string status = score >= 60 ? "Pass" [1] "Fail";

Drag options to blanks, or click blank then click option'

A?

B;

C,

D:

Attempts:

3 left

💡 Hint

Common Mistakes

Using a semicolon or comma instead of a colon.

Omitting the colon entirely.

The ternary operator requires a colon : between the true and false expressions.

4fill in blank

hard

Fill both blanks to assign message based on age.

C Sharp (C#)

int age = 20;
string message = (age >= [1]) ? "Adult" : [2];

Drag options to blanks, or click blank then click option'

A18

B"Minor"

C"Child"

D21

Attempts:

3 left

💡 Hint

Common Mistakes

Using 21 instead of 18 for the age check.

Using "Child" instead of "Minor" for the false part.

If age is 18 or more, message is "Adult"; otherwise, it is "Minor".

5fill in blank

hard

Fill all three blanks to create a dictionary that maps numbers to "Even" or "Odd" strings.

C Sharp (C#)

var parity = new Dictionary<int, string>()
{
    {1, [1],
    {2, [2],
    {3, [3]
};

Drag options to blanks, or click blank then click option'

A"Odd"

B"Even"

Attempts:

3 left

💡 Hint

Common Mistakes

Assigning "Even" to odd numbers.

Mixing up the order of values.

Numbers 1 and 3 are odd, so map to "Odd"; number 2 is even, so map to "Even".