Single-dimensional array declaration in C Sharp (C#) - Mini Project: Build & Apply

Single-dimensional array declaration

📖 Scenario: You are creating a simple program to store the names of fruits in a list. This list will help you keep track of fruits you want to buy from the market.

🎯 Goal: Build a program that declares a single-dimensional array of fruits, sets a size for it, fills it with fruit names, and then prints all the fruit names.

📋 What You'll Learn

Declare a single-dimensional array of strings called fruits with size 4

Assign the fruit names "Apple", "Banana", "Cherry", and "Date" to the array elements

Use a for loop with variable i to iterate over the array

Print each fruit name inside the loop using Console.WriteLine

💡 Why This Matters

🌍 Real World

Arrays are used to store lists of items like names, prices, or scores in many programs.

💼 Career

Knowing how to declare and use arrays is a basic skill for software developers working with data collections.

1

Declare a single-dimensional array

Declare a single-dimensional array of strings called fruits with size 4.

C Sharp (C#)

// Your code here

Hint

Use string[] fruits = new string[4]; to create an array that can hold 4 fruit names.

2

Assign fruit names to the array

Assign the fruit names "Apple", "Banana", "Cherry", and "Date" to the array elements fruits[0], fruits[1], fruits[2], and fruits[3] respectively.

C Sharp (C#)

string[] fruits = new string[4];
// Your code here

Hint

Assign each fruit name to the correct index in the array using fruits[index] = "FruitName";.

3

Use a for loop to iterate over the array

Use a for loop with variable i to iterate over the fruits array from index 0 to 3.

C Sharp (C#)

string[] fruits = new string[4];
fruits[0] = "Apple";
fruits[1] = "Banana";
fruits[2] = "Cherry";
fruits[3] = "Date";

// Your code here

Hint

Use for (int i = 0; i < fruits.Length; i++) to loop through all elements.

4

Print each fruit name

Inside the for loop, use Console.WriteLine(fruits[i]) to print each fruit name.

C Sharp (C#)

string[] fruits = new string[4];
fruits[0] = "Apple";
fruits[1] = "Banana";
fruits[2] = "Cherry";
fruits[3] = "Date";

for (int i = 0; i < fruits.Length; i++)
{
    // Your code here
}

Hint

Use Console.WriteLine(fruits[i]); inside the loop to print each fruit.

Practice

1. Which of the following correctly declares a single-dimensional array of integers in C#?

easy

A. int[] numbers = new int[5];

B. int numbers = new int[5];

C. int[] numbers = int[5];

D. int numbers[] = new int();

Solution

1. Step 1: Understand array declaration syntax

   In C#, a single-dimensional array is declared by specifying the type followed by square brackets and then initializing with 'new' and size.

2. Step 2: Check each option

   int[] numbers = new int[5]; correctly uses 'int[] numbers = new int[5];'. Others have syntax errors or wrong types.

3. Final Answer:

   int[] numbers = new int[5]; -> Option A

4. Quick Check:

   Correct array declaration = int[] numbers = new int[5]; [OK]

Hint: Remember: type[] name = new type[size]; for arrays [OK]

Common Mistakes:

• Forgetting square brackets after type
• Not using 'new' keyword
• Declaring array without size or initializer

2. Which of the following is the correct syntax to declare and initialize a single-dimensional string array with 3 elements in C#?

easy

A. string[] names = new string[2] {"Anna", "Bob", "Cara"};

B. string names[] = {"Anna", "Bob", "Cara"};

C. string[] names = new string {"Anna", "Bob", "Cara"};

D. string[] names = new string[] {"Anna", "Bob", "Cara"};

Solution

1. Step 1: Understand array initialization syntax

   In C#, you can initialize an array with values using 'new type[] { values }' or just '{ values }' if declaration and initialization are combined.

2. Step 2: Check each option

   string[] names = new string[] {"Anna", "Bob", "Cara"}; is fully correct. string[] names = new string[2] {"Anna", "Bob", "Cara"}; incorrectly specifies size 2 with 3 initializers (compile error). string names[] = {"Anna", "Bob", "Cara"}; uses invalid syntax. string[] names = new string {"Anna", "Bob", "Cara"}; invalid syntax (missing array dimensions).

3. Final Answer:

   string[] names = new string[] {"Anna", "Bob", "Cara"}; -> Option D

4. Quick Check:

   Explicit array init with new string[] = string[] names = new string[] {"Anna", "Bob", "Cara"}; [OK]

Hint: Use 'new type[] { ... }' for explicit array initialization [OK]

Common Mistakes:

• Specifying size with initializer list
• Using C-style array syntax
• Omitting 'new' keyword incorrectly

3. What will be the output of the following C# code?

int[] arr = new int[3] {10, 20, 30};
Console.WriteLine(arr[1]);

medium

A. 20

B. 10

C. 30

D. Runtime error

Solution

1. Step 1: Understand array indexing

   Arrays in C# are zero-based, so arr[0] = 10, arr[1] = 20, arr[2] = 30.

2. Step 2: Identify the printed element

   The code prints arr[1], which is 20.

3. Final Answer:

   20 -> Option A

4. Quick Check:

   arr[1] = 20 [OK]

Hint: Remember arrays start at index 0 in C# [OK]

Common Mistakes:

• Confusing index 1 with index 0
• Expecting output to be 10 or 30
• Thinking array indexes start at 1

4. Identify the error in the following C# code snippet:

int[] values;
values = new int[3];
values[3] = 100;

medium

A. Array size is not specified

B. Index out of range error

C. Missing array initialization

D. Syntax error in declaration

Solution

1. Step 1: Check array size and indexing

   The array 'values' is declared with size 3, so valid indexes are 0, 1, and 2.

2. Step 2: Analyze the assignment

   Assigning to values[3] is invalid and causes an IndexOutOfRangeException at runtime.

3. Final Answer:

   Index out of range error -> Option B

4. Quick Check:

   Accessing index 3 in size 3 array causes error [OK]

Hint: Array indexes go from 0 to size-1 only [OK]

Common Mistakes:

• Using index equal to array size
• Forgetting zero-based indexing
• Assuming array auto-expands

5. You want to declare a single-dimensional array of 4 doubles and initialize it with values 1.1, 2.2, 3.3, and 4.4. Which code snippet correctly does this and allows you to change the third element later?

hard

A. double[] data = new double[3] {1.1, 2.2, 3.3, 4.4}; data[2] = 5.5;

B. double[] data = new double[3]; data[2] = 5.5;

C. double[] data = new double[4] {1.1, 2.2, 3.3, 4.4}; data[2] = 5.5;

D. double data[] = new double[] {1.1, 2.2, 3.3, 4.4}; data[3] = 5.5;

Solution

1. Step 1: Check array declaration and initialization

   double[] data = new double[4] {1.1, 2.2, 3.3, 4.4}; data[2] = 5.5; declares an array of size 4 with initial values and allows modification of elements.

2. Step 2: Verify element modification

   double[] data = new double[3] {1.1, 2.2, 3.3, 4.4}; data[2] = 5.5; incorrectly specifies size 3 with 4 initializers (compile error). double data[] = new double[] {1.1, 2.2, 3.3, 4.4}; data[3] = 5.5; uses invalid syntax but index 3 is valid for size 4 array. double[] data = new double[3]; data[2] = 5.5; declares size 3, not 4, missing initialization.

3. Final Answer:

   double[] data = new double[4] {1.1, 2.2, 3.3, 4.4}; data[2] = 5.5; -> Option C

4. Quick Check:

   Explicit size and initializer with modifiable element = double[] data = new double[4] {1.1, 2.2, 3.3, 4.4}; data[2] = 5.5; [OK]

Hint: Use 'new type[size] {values}' to declare and initialize arrays [OK]

Common Mistakes:

• Mismatching array size and initializer count
• Using wrong index for element change
• Omitting 'new' keyword in some contexts