Pattern matching in a switch statement lets you check an expression against different patterns, not just fixed values. It helps you test types, properties, or conditions directly in each case.
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beginner
How do you match a type in a switch case using pattern matching?
You write the type name followed by a variable name, like case int number:. This matches if the value is an int and assigns it to number.
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intermediate
What does the when keyword do in a switch case?
The when keyword adds an extra condition to a case. The case matches only if the pattern matches and the when condition is true.
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intermediate
Explain the difference between case int n: and case int n when n > 0:.
case int n: matches any integer and assigns it to n. case int n when n > 0: matches only positive integers because of the when condition.
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beginner
Can you use pattern matching in switch expressions as well as statements?
Yes! Pattern matching works in both switch statements and switch expressions, allowing concise and readable code for selecting values based on patterns.
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What does case string s: do in a switch statement?
AMatches any string and assigns it to s
BMatches only empty strings
CMatches any integer and assigns it to s
DMatches null values only
✗ Incorrect
The case matches any value of type string and assigns it to the variable s.
Which keyword adds an extra condition to a switch case pattern?
Aif
Bwhere
Cwhen
Dcase
✗ Incorrect
The 'when' keyword adds a condition that must be true for the case to match.
What happens if no pattern matches in a switch statement with pattern matching?
AThe switch statement is skipped
BThe program crashes
CThe first case runs anyway
DThe default case runs if provided
✗ Incorrect
If no pattern matches, the default case runs if it exists; otherwise, no case runs.
Which of these is a valid pattern matching case in C#?
Acase n int:
Bcase int n when n < 10:
Ccase (int) n:
Dcase int:
✗ Incorrect
Option B correctly uses type matching with a variable and a when condition.
Can pattern matching in switch check properties of an object?
Describe how pattern matching improves switch statements in C#.
Think about how you can check more than just fixed values.
You got /4 concepts.
Explain how to use the 'when' keyword in a switch case with an example.
It adds extra conditions to cases.
You got /4 concepts.
Practice
(1/5)
1. What does pattern matching in a switch statement primarily help you do in C#?
easy
A. Check an object's type and properties in a clear way
B. Loop through collections more efficiently
C. Declare variables with less code
D. Handle exceptions automatically
Solution
Step 1: Understand pattern matching purpose
Pattern matching in switch lets you test an object's type and properties clearly.
Step 2: Compare with other options
Looping, variable declaration, and exception handling are unrelated to pattern matching in switch.
Final Answer:
Check an object's type and properties in a clear way -> Option A
Quick Check:
Pattern matching = type and property checks [OK]
Hint: Pattern matching checks types and conditions clearly [OK]
Common Mistakes:
Confusing pattern matching with loops
Thinking it handles exceptions
Believing it declares variables automatically
2. Which of the following is the correct syntax to match an integer variable num equal to 10 using pattern matching in a switch expression?
easy
A. case int n when n == 10:
B. case int n == 10:
C. case int n => 10:
D. case int n is 10:
Solution
Step 1: Recall correct pattern matching syntax
To match a value with a condition, use case Type variable when condition:.
Step 2: Check each option
case int n when n == 10: uses when n == 10, which is correct. Others use invalid syntax.
Final Answer:
case int n when n == 10: -> Option A
Quick Check:
Use 'when' for conditions in pattern matching [OK]
Hint: Use 'when' keyword for conditions in switch patterns [OK]
Common Mistakes:
Using '==' directly after case without 'when'
Using '=>' or 'is' incorrectly in case
Omitting the variable name
3. What will be the output of this C# code?
object obj = 42;
switch (obj)
{
case int n when n > 40:
Console.WriteLine("Greater than 40");
break;
case int n:
Console.WriteLine("Integer");
break;
default:
Console.WriteLine("Other");
break;
}
medium
A. Integer
B. Other
C. Greater than 40
D. No output (compile error)
Solution
Step 1: Identify the object type and value
obj is an integer with value 42.
Step 2: Evaluate switch cases in order
First case matches int n when n > 40, which is true for 42, so prints "Greater than 40" and breaks.
Final Answer:
Greater than 40 -> Option C
Quick Check:
Pattern with 'when' matched first [OK]
Hint: Check cases top to bottom; first match runs [OK]
Common Mistakes:
Ignoring the 'when' condition
Assuming second case runs first
Thinking default runs for int
4. Identify the error in this switch statement using pattern matching:
object val = "hello";
switch (val)
{
case string s when s.Length > 3
Console.WriteLine("Long string");
break;
default:
Console.WriteLine("Other");
break;
}
medium
A. Cannot use 'when' with string type
B. Missing colon ':' after case pattern
C. Missing parentheses around condition
D. Incorrect variable name in case
Solution
Step 1: Check switch case syntax
Each case pattern must end with a colon ':' before the statements.
Step 2: Locate missing colon
The case line lacks ':' after when s.Length > 3, causing syntax error.
Final Answer:
Missing colon ':' after case pattern -> Option B
Quick Check:
Case patterns need ':' after condition [OK]
Hint: Always put ':' after case pattern line [OK]
Common Mistakes:
Forgetting ':' after case pattern
Adding parentheses around 'when' condition
Thinking 'when' can't be used with strings
5. Given a list of objects items containing integers and strings, how would you use pattern matching in a switch expression to return a new list of strings where: - Integers greater than 10 become "Big number" - Strings longer than 5 characters become "Long text" - All others become "Other"?
Which code snippet correctly implements this?
hard
A. items.Select(item => item switch {
int n when n > 10: "Big number",
string s when s.Length > 5: "Long text",
_ => "Other"
}).ToList();
B. items.Select(item => switch (item) {
case int n if n > 10: "Big number";
case string s if s.Length > 5: "Long text";
default: "Other";
}).ToList();
C. items.Select(item => item switch {
int n if n > 10: "Big number",
string s if s.Length > 5: "Long text",
_ => "Other"
}).ToList();
D. items.Select(item => item switch {
int n when n > 10 => "Big number",
string s when s.Length > 5 => "Long text",
_ => "Other"
}).ToList();
Solution
Step 1: Understand switch expression syntax
Switch expressions use '=>' for cases, and 'when' for conditions.
Step 2: Check each option's syntax
items.Select(item => item switch {
int n when n > 10 => "Big number",
string s when s.Length > 5 => "Long text",
_ => "Other"
}).ToList(); uses correct 'item switch { case => result }' with 'when' and '=>'. Other options use invalid syntax ('switch' inside lambda or 'if' instead of 'when'). items.Select(item => item switch {
int n when n > 10: "Big number",
string s when s.Length > 5: "Long text",
_ => "Other"
}).ToList(); uses ':' instead of '=>', which is invalid in switch expressions.
Final Answer:
items.Select(item => item switch {
int n when n > 10 => "Big number",
string s when s.Length > 5 => "Long text",
_ => "Other"
}).ToList(); -> Option D
Quick Check:
Switch expressions use '=>' and 'when' [OK]
Hint: Use '=>' and 'when' in switch expressions for conditions [OK]
Common Mistakes:
Using ':' instead of '=>' in switch expressions
Using 'if' instead of 'when' for conditions
Trying to put 'switch' keyword inside lambda
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