Jagged arrays in C Sharp (C#) - Mini Project: Build & Apply

Jagged Arrays in C#

📖 Scenario: You are organizing seating arrangements for different rooms in a community center. Each room has a different number of chairs arranged in rows. You want to represent this seating using jagged arrays, where each row can have a different number of chairs.

🎯 Goal: Build a C# program that creates a jagged array representing the seating arrangement, sets a threshold for minimum chairs per row, finds rows that meet this threshold, and prints the count of such rows.

📋 What You'll Learn

Create a jagged array called seating with 3 rows having exact chair counts: 4, 2, and 5 chairs respectively.

Create an integer variable called minChairs and set it to 3.

Use a for loop with variable i to count how many rows in seating have chairs greater than or equal to minChairs.

Print the count using Console.WriteLine.

💡 Why This Matters

🌍 Real World

Jagged arrays are useful when you have collections of collections with varying sizes, like seating arrangements, schedules, or grouped data.

💼 Career

Understanding jagged arrays helps in software development tasks involving complex data structures, memory optimization, and flexible data storage.

1

Create the jagged array seating

Create a jagged array called seating with 3 rows. The first row should have 4 chairs, the second row 2 chairs, and the third row 5 chairs. Use exact values: new int[][] { new int[4], new int[2], new int[5] }.

C Sharp (C#)

// Create the jagged array seating with 3 rows having 4, 2, and 5 chairs
// Your code here

Need a hint?

Use int[][] seating = new int[][] { new int[4], new int[2], new int[5] }; to create the jagged array.

2

Set the minimum chairs threshold

Create an integer variable called minChairs and set it to 3.

C Sharp (C#)

int[][] seating = new int[][] { new int[4], new int[2], new int[5] };
// Create an integer variable minChairs and set it to 3
// Your code here

Need a hint?

Write int minChairs = 3; to set the threshold.

3

Count rows with chairs >= minChairs

Create an integer variable called count and set it to 0. Use a for loop with variable i to iterate over seating. Inside the loop, check if seating[i].Length is greater than or equal to minChairs. If yes, increase count by 1.

C Sharp (C#)

int[][] seating = new int[][] { new int[4], new int[2], new int[5] };
int minChairs = 3;
// Create count variable and use for loop to count rows with chairs >= minChairs
// Your code here

Need a hint?

Use for (int i = 0; i < seating.Length; i++) and inside check if (seating[i].Length >= minChairs).

4

Print the count of rows meeting the threshold

Use Console.WriteLine to print the value of count.

C Sharp (C#)

int[][] seating = new int[][] { new int[4], new int[2], new int[5] };
int minChairs = 3;
int count = 0;
for (int i = 0; i = minChairs)
    {
        count++;
    }
}
// Print the count variable
// Your code here

Need a hint?

Use Console.WriteLine(count); to show the result.