Bird
Raised Fist0
C Sharp (C#)programming~5 mins

Integer types and their ranges in C Sharp (C#) - Time & Space Complexity

Choose your learning style10 modes available
Time Complexity: Integer types and their ranges
O(n)
Understanding Time Complexity

We want to understand how the size of integer types affects operations in C#.

How does the range of integers impact the work done by the program?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.


int SumUpTo(int n) {
    int sum = 0;
    for (int i = 1; i <= n; i++) {
        sum += i;
    }
    return sum;
}

This code sums all numbers from 1 up to n using an integer variable.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

  • Primary operation: The for-loop adding numbers one by one.
  • How many times: It runs exactly n times, where n is the input number.
How Execution Grows With Input

As n grows, the number of additions grows the same way.

Input Size (n)Approx. Operations
1010 additions
100100 additions
10001000 additions

Pattern observation: The work grows directly with n, so doubling n doubles the work.

Final Time Complexity

Time Complexity: O(n)

This means the time to finish grows in a straight line as the input number gets bigger.

Common Mistake

[X] Wrong: "Using bigger integer types makes the loop run faster or slower."

[OK] Correct: The integer type size affects memory but does not change how many times the loop runs or how many additions happen.

Interview Connect

Understanding how input size affects loops is a key skill. It helps you explain how your code will behave with bigger numbers.

Self-Check

"What if we changed the loop to count down from n to 1? How would the time complexity change?"

Practice

(1/5)
1. Which C# integer type can store values from -128 to 127?
easy
A. int
B. byte
C. short
D. sbyte

Solution

  1. Step 1: Recall the range of sbyte

    The sbyte type stores signed 8-bit integers from -128 to 127.
  2. Step 2: Compare with other types

    byte stores 0 to 255 (unsigned), short stores -32,768 to 32,767, and int stores much larger values.
  3. Final Answer:

    sbyte -> Option D
  4. Quick Check:

    Range -128 to 127 = sbyte [OK]
Hint: Remember sbyte is signed 8-bit: -128 to 127 [OK]
Common Mistakes:
  • Confusing byte (unsigned) with sbyte
  • Choosing short which has a larger range
  • Assuming int is smallest
2. Which of the following is the correct way to declare a variable of type uint in C#?
easy
A. uint number = -1;
B. uint number = 4294967295;
C. uint number = 4294967296;
D. uint number = 3.14;

Solution

  1. Step 1: Understand uint range

    uint is unsigned 32-bit integer with range 0 to 4,294,967,295.
  2. Step 2: Check each assignment

    uint number = -1; assigns -1 (negative) which is invalid. uint number = 4294967295; assigns max valid value 4,294,967,295. uint number = 4294967296; assigns 4,294,967,296 which is too large. uint number = 3.14; assigns a decimal which is invalid for integer type.
  3. Final Answer:

    uint number = 4294967295; -> Option B
  4. Quick Check:

    uint max = 4294967295 [OK]
Hint: uint stores 0 to 4,294,967,295 only [OK]
Common Mistakes:
  • Assigning negative values to unsigned types
  • Using values larger than max range
  • Assigning decimal numbers to integer types
3. What will be the output of this C# code?
short a = 30000;
short b = 10000;
int c = a + b;
Console.WriteLine(c);
medium
A. 40000
B. -25536
C. OverflowException
D. Compile-time error

Solution

  1. Step 1: Understand variable types and addition

    Variables a and b are short (16-bit signed), but addition promotes them to int automatically.
  2. Step 2: Calculate the sum and output

    30000 + 10000 = 40000 fits in int range, so c stores 40000 and prints it.
  3. Final Answer:

    40000 -> Option A
  4. Quick Check:

    30000 + 10000 = 40000 [OK]
Hint: short addition promotes to int, no overflow here [OK]
Common Mistakes:
  • Expecting overflow because sum exceeds short max
  • Thinking addition stays in short type
  • Confusing runtime overflow with compile error
4. Identify the error in this C# code snippet:
byte x = 255;
byte y = 1;
byte z = (byte)(x + y);
Console.WriteLine(z);
medium
A. Output is 0 due to overflow wrap-around
B. Compile-time error due to overflow
C. No error, output is 256
D. Runtime exception thrown

Solution

  1. Step 1: Analyze addition and casting

    Addition of x + y is done as int (255 + 1 = 256). Casting to byte truncates to 8 bits.
  2. Step 2: Understand overflow wrap-around

    Since byte max is 255, 256 wraps around to 0 due to overflow without exception.
  3. Final Answer:

    Output is 0 due to overflow wrap-around -> Option A
  4. Quick Check:

    256 mod 256 = 0 [OK]
Hint: Casting int > 255 to byte wraps around [OK]
Common Mistakes:
  • Expecting output 256 which is invalid for byte
  • Thinking compile or runtime error occurs
  • Ignoring overflow wrap-around behavior
5. You need to store the population of a city which can be up to 5 billion. Which C# integer type should you use to avoid overflow?
hard
A. int
B. uint
C. long
D. short

Solution

  1. Step 1: Check the required range

    5 billion is 5,000,000,000 which exceeds int max (2,147,483,647) and uint max (4,294,967,295).
  2. Step 2: Choose type with sufficient range

    long is a signed 64-bit integer with range ±9 quintillion, enough to store 5 billion safely.
  3. Final Answer:

    long -> Option C
  4. Quick Check:

    5 billion < long max [OK]
Hint: Use long for numbers bigger than int or uint max [OK]
Common Mistakes:
  • Choosing int or uint which are too small
  • Using short which is very small
  • Not considering signed vs unsigned range
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard