IoU (Intersection over Union) in Computer Vision - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to calculate the area of a bounding box given its coordinates.

Computer Vision

def box_area(x1, y1, x2, y2):
    return (x2 - x1) [1] (y2 - y1)

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A*

B-

C+

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using addition instead of multiplication.

Subtracting the coordinates incorrectly.

The area of a rectangle is width times height, so we multiply the width (x2 - x1) by the height (y2 - y1).

2fill in blank

medium

Complete the code to find the coordinates of the intersection box between two bounding boxes.

Computer Vision

def intersection_box(boxA, boxB):
    x_left = max(boxA[0], boxB[0])
    y_top = max(boxA[1], boxB[1])
    x_right = min(boxA[2], boxB[2])
    y_bottom = [1](boxA[3], boxB[3])
    return x_left, y_top, x_right, y_bottom

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Amax

Bsum

Cabs

Dmin

Attempts:

3 left

💡 Hint

Common Mistakes

Using max instead of min for bottom coordinate.

Mixing up x and y coordinates.

The bottom coordinate of the intersection is the minimum of the two boxes' bottom y-coordinates.

3fill in blank

hard

Fix the error in the code that calculates the intersection area of two bounding boxes.

Computer Vision

def intersection_area(boxA, boxB):
    x_left, y_top, x_right, y_bottom = intersection_box(boxA, boxB)
    if x_right < x_left or y_bottom < y_top:
        return 0
    return (x_right - x_left) [1] (y_bottom - y_top)

Drag options to blanks, or click blank then click option'

A-

B+

C*

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using addition instead of multiplication.

Returning negative area values.

The intersection area is width times height, so multiply the differences in x and y.

4fill in blank

hard

Fill both blanks to compute the union area of two bounding boxes.

Computer Vision

def union_area(boxA, boxB):
    areaA = box_area(*boxA)
    areaB = box_area(*boxB)
    inter_area = intersection_area(boxA, boxB)
    return areaA [1] areaB [2] inter_area

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A+

B-

C*

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Adding intersection area instead of subtracting.

Multiplying areas instead of adding.

The union area is the sum of both areas minus the intersection area to avoid double counting.

5fill in blank

hard

Fill all three blanks to complete the IoU calculation function.

Computer Vision

def iou(boxA, boxB):
    inter_area = intersection_area(boxA, boxB)
    union = union_area(boxA, boxB)
    if union == 0:
        return 0
    return [3](inter_area [1] union [2] 1.0)

Drag options to blanks, or click blank then click option'

A/

B*

C==

Dfloat

Attempts:

3 left

💡 Hint

Common Mistakes

Using equality (==) instead of division (/).

Not converting to float causing integer division.

IoU is intersection area divided by union area. Multiplying by 1.0 and converting to float ensures a float result.