Asymmetric encryption (RSA) in Computer Networks - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to identify the key used for encryption in RSA.

Computer Networks

encrypted_message = encrypt(message, [1])

Drag options to blanks, or click blank then click option'

Apublic_key

Bprivate_key

Cshared_key

Dsession_key

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing the private key with the public key for encryption.

Thinking that a shared or session key is used in RSA encryption.

In RSA, the public key is used to encrypt messages so that only the holder of the private key can decrypt them.

2fill in blank

medium

Complete the code to identify the key used for decryption in RSA.

Computer Networks

decrypted_message = decrypt(encrypted_message, [1])

Drag options to blanks, or click blank then click option'

Asession_key

Bpublic_key

Cprivate_key

Dshared_key

Attempts:

3 left

💡 Hint

Common Mistakes

Using the public key for decryption instead of the private key.

Confusing shared or session keys with RSA keys.

In RSA, the private key is used to decrypt messages that were encrypted with the public key.

3fill in blank

hard

Fix the error in the RSA key generation code by selecting the correct prime number.

Computer Networks

p = [1]  # First prime number for RSA key generation

Drag options to blanks, or click blank then click option'

A17

B15

C21

D20

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing a composite number instead of a prime number.

Not verifying the primality of the number before using it.

RSA requires prime numbers for key generation. Among the options, 17 is a prime number, while 15, 20, and 21 are not.

4fill in blank

hard

Fill both blanks to complete the RSA public key generation formula.

Computer Networks

public_key = ([1], [2])  # (e, [2])

Drag options to blanks, or click blank then click option'

Ae

Bn

Cd

Dp

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing the private exponent 'd' with the public exponent 'e'.

Using prime numbers directly instead of the modulus 'n'.

The RSA public key consists of e (the public exponent) and n (the modulus).

5fill in blank

hard

Fill all three blanks to complete the RSA decryption formula.

Computer Networks

decrypted_message = ([1] ** [2]) % [3]

Drag options to blanks, or click blank then click option'

Aencrypted_message

Bd

Cn

De

Attempts:

3 left

💡 Hint

Common Mistakes

Using the public exponent 'e' instead of the private exponent 'd' for decryption.

Forgetting to use the modulus operation.

RSA decryption uses the formula: message = (encrypted_message ^ d) mod n, where d is the private key exponent and n is the modulus.