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Computer Networksknowledge~10 mins

TCP flow control (sliding window) in Computer Networks - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the sentence to describe the purpose of TCP flow control.

Computer Networks
TCP flow control uses a [1] to manage the amount of data sent before receiving an acknowledgment.
Drag options to blanks, or click blank then click option'
Achecksum
Brouting table
Csliding window
DIP address
Attempts:
3 left
💡 Hint
Common Mistakes
Confusing flow control with error checking methods like checksum.
Thinking routing tables are involved in flow control.
2fill in blank
medium

Complete the sentence to explain what the window size represents in TCP flow control.

Computer Networks
The window size in TCP flow control represents the [1] of data the sender can transmit without waiting for an acknowledgment.
Drag options to blanks, or click blank then click option'
Amaximum amount
Bminimum amount
Caverage amount
Dtotal amount
Attempts:
3 left
💡 Hint
Common Mistakes
Confusing maximum with minimum or average.
Thinking the window size is the total data to be sent.
3fill in blank
hard

Fix the error in the statement about sliding window movement.

Computer Networks
The sliding window moves forward when the sender receives a [1] from the receiver.
Drag options to blanks, or click blank then click option'
Anegative acknowledgment
Bpositive acknowledgment
Ctimeout
Dreset signal
Attempts:
3 left
💡 Hint
Common Mistakes
Thinking the window moves on timeout or negative acknowledgment.
Confusing reset signals with acknowledgments.
4fill in blank
hard

Fill both blanks to complete the explanation of how the sliding window adjusts.

Computer Networks
The sender adjusts the window size based on the [1] value sent by the receiver and [2] network conditions.
Drag options to blanks, or click blank then click option'
Aadvertised window
Bpacket loss
Ccongestion
Dtimeout
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing up advertised window with timeout or packet loss.
Ignoring network congestion effects.
5fill in blank
hard

Fill all three blanks to complete the dictionary comprehension representing TCP window updates.

Computer Networks
window_updates = [1]: [2] for [3] in packets if packets[[3]] > 0
Drag options to blanks, or click blank then click option'
Aseq_num
Bwindow_size
Dpacket
Attempts:
3 left
💡 Hint
Common Mistakes
Using packet as key instead of sequence number.
Not filtering packets with positive size.

Practice

(1/5)
1. What is the main purpose of the sliding window in TCP flow control?
easy
A. To control the amount of data sent before receiving an acknowledgment
B. To encrypt data during transmission
C. To assign IP addresses to devices
D. To route packets between networks

Solution

  1. Step 1: Understand the role of sliding window in TCP

    The sliding window limits how much data the sender can transmit before waiting for an acknowledgment from the receiver.
  2. Step 2: Identify the purpose among options

    Only To control the amount of data sent before receiving an acknowledgment describes controlling data flow using acknowledgments, which matches the sliding window's purpose.
  3. Final Answer:

    To control the amount of data sent before receiving an acknowledgment -> Option A
  4. Quick Check:

    Sliding window controls data flow = To control the amount of data sent before receiving an acknowledgment [OK]
Hint: Sliding window limits unacknowledged data sent [OK]
Common Mistakes:
  • Confusing flow control with encryption
  • Mixing routing with flow control
  • Thinking sliding window assigns IPs
2. Which of the following correctly describes the sliding window size in TCP?
easy
A. It is fixed and never changes during the connection
B. It is set by the IP address of the sender
C. It is always equal to the maximum segment size (MSS)
D. It increases or decreases based on acknowledgments received

Solution

  1. Step 1: Recall how sliding window size behaves

    The window size changes dynamically as acknowledgments arrive, allowing the sender to send more data.
  2. Step 2: Match behavior to options

    It increases or decreases based on acknowledgments received correctly states the window size adjusts based on acknowledgments, unlike fixed size or unrelated factors.
  3. Final Answer:

    It increases or decreases based on acknowledgments received -> Option D
  4. Quick Check:

    Window size changes with ACKs = It increases or decreases based on acknowledgments received [OK]
Hint: Window size changes with ACKs, not fixed [OK]
Common Mistakes:
  • Assuming window size is fixed
  • Confusing window size with MSS
  • Linking window size to IP address
3. Consider a TCP connection with a window size of 4 segments. The sender has sent segments 1 to 4. The receiver acknowledges segment 2. Which segments can the sender send next?
medium
A. Segments 5, 6, and 7
B. Segments 3 and 4 again
C. Segments 5 and 6
D. No new segments until all are acknowledged

Solution

  1. Step 1: Understand sliding window movement after ACK

    When segment 2 is acknowledged, the window slides forward, allowing sending of new segments beyond 4.
  2. Step 2: Calculate which segments fit in the window

    Window size is 4, segments 1 and 2 acknowledged, so segments 3 and 4 are still unacknowledged. The sender can send segments 5 and 6 to fill the window.
  3. Final Answer:

    Segments 5 and 6 -> Option C
  4. Quick Check:

    ACK 2 slides window, send next 2 segments = Segments 5 and 6 [OK]
Hint: ACK moves window; send new segments within window size [OK]
Common Mistakes:
  • Resending unacknowledged segments unnecessarily
  • Sending more segments than window size allows
  • Waiting for all segments to be acknowledged
4. A TCP sender has a window size of 3 segments and has sent segments 1, 2, and 3. The receiver sends an acknowledgment for segment 1 only. The sender mistakenly sends segment 4 and 5 immediately. What is the problem with this behavior?
medium
A. It violates the sliding window limit and may cause congestion
B. It improves throughput by sending more data
C. It is correct because ACK 1 means all previous segments are received
D. It causes the receiver to close the connection

Solution

  1. Step 1: Analyze window size and ACK received

    The window size is 3, and only segment 1 is acknowledged, so segments 2 and 3 are still unacknowledged.
  2. Step 2: Identify why sending segments 4 and 5 is wrong

    Sending segments 4 and 5 exceeds the allowed window size, risking congestion and data loss.
  3. Final Answer:

    It violates the sliding window limit and may cause congestion -> Option A
  4. Quick Check:

    Sending beyond window size causes issues = It violates the sliding window limit and may cause congestion [OK]
Hint: Don't send beyond window size before ACKs arrive [OK]
Common Mistakes:
  • Assuming ACK 1 means all segments received
  • Ignoring window size limits
  • Thinking sending more data always helps
5. In a TCP connection, the sender's window size is 5 segments. The receiver's buffer can only hold 3 segments. How should the sliding window mechanism adapt to prevent buffer overflow?
hard
A. The sender should keep sending 5 segments regardless
B. The sender should reduce the window size to 3 segments
C. The receiver should increase its buffer size to 5 segments
D. The sender should stop sending any segments

Solution

  1. Step 1: Understand receiver buffer limits

    The receiver can only hold 3 segments, so sending more than 3 risks overflow and data loss.
  2. Step 2: Adjust sender window size accordingly

    The sliding window size must match or be less than the receiver's buffer to avoid overflow, so the sender should reduce its window size to 3.
  3. Final Answer:

    The sender should reduce the window size to 3 segments -> Option B
  4. Quick Check:

    Sender window ≤ receiver buffer to prevent overflow = The sender should reduce the window size to 3 segments [OK]
Hint: Match sender window to receiver buffer size [OK]
Common Mistakes:
  • Ignoring receiver buffer size
  • Assuming receiver buffer can always expand
  • Stopping sending completely without reason
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10 questions~5 mineasy hard