Regular expressions for token patterns in Compiler Design - Time & Space Complexity
We want to understand how the time to match tokens using regular expressions changes as the input grows.
How does the matching process scale when scanning longer source code?
Analyze the time complexity of the following token matching using regular expressions.
for each token_pattern in token_patterns:
if regex_match(token_pattern, input_string):
return matched_token
return no_match
This code tries each token pattern one by one to find a match at the start of the input string.
Look for repeated checks and scans.
- Primary operation: Matching each regular expression against the input string.
- How many times: Once per token pattern, scanning input characters as needed.
As the input string gets longer, each regex may need to scan more characters to confirm a match or failure.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | Checks each pattern scanning up to 10 chars |
| 100 | Checks each pattern scanning up to 100 chars |
| 1000 | Checks each pattern scanning up to 1000 chars |
Pattern observation: The work grows roughly in proportion to the input length times the number of token patterns.
Time Complexity: O(m * n)
This means the time grows linearly with both the number of token patterns (m) and the input length (n).
[X] Wrong: "Matching tokens with regex is always constant time regardless of input size."
[OK] Correct: Regex matching scans input characters, so longer inputs take more time to check.
Understanding how regex matching scales helps you explain lexer performance and design efficient tokenizers.
What if we used a single combined regex for all tokens instead of checking each pattern separately? How would the time complexity change?
Practice
Solution
Step 1: Understand the role of regular expressions
Regular expressions are used to describe patterns that match sequences of characters.Step 2: Connect to compiler design
In compiler design, these patterns help identify tokens like keywords, identifiers, and symbols.Final Answer:
To define patterns for recognizing tokens in source code -> Option AQuick Check:
Regular expressions = token patterns [OK]
- Confusing regular expressions with code execution
- Thinking they optimize code performance
- Mixing up with memory management
Solution
Step 1: Identify the pattern for an identifier
An identifier starts with a letter, then can have letters or digits.Step 2: Match the regular expression
[a-zA-Z][a-zA-Z0-9]* matches one letter [a-zA-Z] followed by zero or more letters or digits [a-zA-Z0-9]*.Final Answer:
[a-zA-Z][a-zA-Z0-9]* -> Option AQuick Check:
Letter + letters/digits = [a-zA-Z][a-zA-Z0-9]* [OK]
- Starting identifier with a digit
- Using + instead of * incorrectly
- Allowing digits as first character
\d{3}-\d{2}-\d{4}, what kind of token does it match?Solution
Step 1: Analyze the regular expression pattern
\d{3} means exactly 3 digits, then a dash, then 2 digits, dash, then 4 digits.Step 2: Identify the token format
This matches the US Social Security Number format: 3 digits - 2 digits - 4 digits.Final Answer:
A US Social Security Number format -> Option CQuick Check:
\d{3}-\d{2}-\d{4} = SSN format [OK]
- Confusing with date formats
- Assuming phone number format
- Ignoring exact digit counts
\d+\.\d*Solution
Step 1: Understand the pattern meaning
\d+ means one or more digits, \. means a literal dot, \d* means zero or more digits after dot.Step 2: Check what numbers it matches
This matches numbers with a decimal point and optional digits after it, but does not match integers without a dot.Final Answer:
It does not allow numbers without decimal part -> Option DQuick Check:
Pattern requires dot, so no integers [OK]
- Thinking dot is unescaped
- Assuming digits after dot are mandatory
- Confusing * and + quantifiers
if or else but not identifiers containing these as substrings?Solution
Step 1: Understand the requirement
We want to match exactly the words 'if' or 'else', not parts of longer words.Step 2: Use word boundaries
\b marks word boundaries, so \b(if|else)\b matches only whole words 'if' or 'else'.Step 3: Check other options
(if|else)+ allows repeated keywords, if|else matches substrings anywhere, [ifelse]+ matches any combination of letters i,f,e,l,s.Final Answer:
\b(if|else)\b -> Option BQuick Check:
Word boundaries ensure exact keyword match [OK]
- Not using word boundaries
- Using character classes instead of groups
- Allowing partial matches inside identifiers
Ready to prove it?
Pass the test and this pattern moves unknown
