Implementing a lexical analyzer in Compiler Design - Time & Space Complexity
When building a lexical analyzer, it is important to understand how the time it takes to process input grows as the input gets larger.
We want to know how the analyzer's work increases as the source code size increases.
Analyze the time complexity of the following code snippet.
function lexicalAnalyzer(input) {
let position = 0;
while (position < input.length) {
let token = getNextToken(input, position);
position += token.length;
}
}
function getNextToken(input, start) {
// scans characters from start to identify next token
// returns token with its length
}
This code reads the input string from start to end, extracting tokens one by one.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Scanning characters in the input string to identify tokens.
- How many times: Each character is examined once as the position moves forward through the input.
As the input size grows, the analyzer processes more characters, so the work grows roughly in direct proportion.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | About 10 character scans |
| 100 | About 100 character scans |
| 1000 | About 1000 character scans |
Pattern observation: The number of operations grows linearly with input size.
Time Complexity: O(n)
This means the time to analyze grows directly in proportion to the length of the input.
[X] Wrong: "The lexical analyzer checks every character multiple times, so it must be slower than linear."
[OK] Correct: The analyzer moves forward through the input without going back, so each character is processed once, keeping the work linear.
Understanding how lexical analyzers scale with input size shows you can reason about program efficiency, a key skill in many coding challenges and real projects.
"What if the lexical analyzer had to backtrack and re-examine characters? How would the time complexity change?"
Practice
Solution
Step 1: Understand the role of lexical analyzer
A lexical analyzer reads the input text and divides it into tokens like keywords, identifiers, and symbols.Step 2: Differentiate from other compiler phases
It does not execute code, optimize, or generate machine code; those are later phases.Final Answer:
Break input text into meaningful tokens -> Option AQuick Check:
Lexical analyzer = tokenization [OK]
- Confusing lexical analysis with code execution
- Thinking it optimizes or generates machine code
- Assuming it handles syntax errors
Solution
Step 1: Recognize token pattern syntax
Token patterns use regular expressions; [a-zA-Z_][a-zA-Z0-9_]* matches identifiers starting with letter or underscore.Step 2: Check other options for correctness
token = (123)+ uses invalid syntax for token pattern; C uses braces incorrectly; D is not a valid pattern.Final Answer:
token = [a-zA-Z_][a-zA-Z0-9_]* -> Option BQuick Check:
Valid regex pattern = token = [a-zA-Z_][a-zA-Z0-9_]* [OK]
- Using invalid characters in token patterns
- Confusing literal strings with patterns
- Ignoring start character rules
int x = 10;, what tokens will a lexical analyzer produce?Solution
Step 1: Identify tokens in the input
The lexical analyzer splits by language rules: keyword 'int', identifier 'x', operator '=', number '10', and symbol ';'.Step 2: Compare with options
["int", "x", "=", "10", ";"] correctly lists all tokens separately. Others combine tokens incorrectly or split numbers wrongly.Final Answer:
["int", "x", "=", "10", ";"] -> Option CQuick Check:
Tokens = separate meaningful units [OK]
- Combining multiple tokens into one
- Splitting numbers into digits
- Ignoring punctuation as tokens
NUMBER = [0-9]+(.[0-9]+)?Solution
Step 1: Analyze the regex pattern
The dot (.) in regex means any character; to match a literal dot, it must be escaped as \.Step 2: Check other parts of the pattern
Plus (+) is correct for one or more digits; square brackets and parentheses are valid here.Final Answer:
Dot (.) should be escaped as \. -> Option DQuick Check:
Escape dot for literal period [OK]
- Not escaping dot causing wrong matches
- Changing quantifiers unnecessarily
- Removing valid grouping parentheses
Solution
Step 1: Understand comment handling
Comments are ignored by the compiler; the lexical analyzer must detect comment start and end patterns and skip their content.Step 2: Evaluate other options
Converting comments into tokens or treating them as errors is incorrect; storing as identifiers is wrong.Final Answer:
By recognizing comment patterns and skipping them -> Option AQuick Check:
Skip comments during tokenization [OK]
- Tokenizing comments as code
- Raising errors on comments
- Confusing comments with identifiers
Ready to prove it?
Pass the test and this pattern moves unknown
