Why do programmers use command line arguments in C programs?
Think about how programs can get information from users before running.
Command line arguments let users give input values directly when they start the program, so the program can use those values without asking for input during execution.
What is the output of this C program if run as ./prog Hello World?
#include <stdio.h> int main(int argc, char *argv[]) { printf("%d\n", argc); printf("%s\n", argv[1]); return 0; }
Remember that argc counts the program name as the first argument.
The program counts 3 arguments: the program name, "Hello", and "World". argv[1] is "Hello".
What error will this program produce when run with no arguments?
#include <stdio.h> int main(int argc, char *argv[]) { printf("First argument: %s\n", argv[1]); return 0; }
Think about what happens if you try to access an argument that was not given.
If no arguments are given, argc is 1 and argv[1] does not exist, causing a segmentation fault.
Which of these is the correct way to declare the main function to use command line arguments in C?
Remember the order and return type for the standard main function.
The standard main function returns int and takes argc first, then argv as an array of pointers to char.
If a program is run as ./app -f file.txt -v, what is the value of argc inside main?
Count the program name and each separate word as one argument.
The arguments are: "./app", "-f", "file.txt", "-v" making 4 arguments, so argc is 4.