Why bitwise operations are needed in C - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to perform a bitwise AND operation between a and b.

C

int result = a [1] b;

Drag options to blanks, or click blank then click option'

A&&

B|

C^

D&

Attempts:

3 left

💡 Hint

Common Mistakes

Using logical AND (&&) instead of bitwise AND (&).

Using bitwise OR (|) instead of AND.

The bitwise AND operator & compares each bit of two integers and returns 1 only if both bits are 1.

2fill in blank

medium

Complete the code to set the 3rd bit of variable flags using bitwise OR.

C

flags = flags [1] (1 << 2);

Drag options to blanks, or click blank then click option'

A|

B<<

C^

D&

Attempts:

3 left

💡 Hint

Common Mistakes

Using bitwise AND (&) which clears bits.

Using XOR (^) which toggles bits.

The bitwise OR operator | sets a bit to 1 if either bit is 1. Shifting 1 by 2 sets the 3rd bit.

3fill in blank

hard

Fix the error in the code to clear the 2nd bit of variable status.

C

status = status [1] ~(1 << 1);

Drag options to blanks, or click blank then click option'

A|

B^

C&

D~

Attempts:

3 left

💡 Hint

Common Mistakes

Using OR (|) which sets bits instead of clearing.

Using XOR (^) which toggles bits.

Bitwise AND with the negated mask clears the targeted bit. Using & with ~(1 << 1) clears the 2nd bit.

4fill in blank

hard

Fill both blanks to check if the 4th bit of num is set.

C

if ((num [1] (1 [2] 3)) != 0) {
    // bit is set
}

Drag options to blanks, or click blank then click option'

A&

B<<

C>>

D|

Attempts:

3 left

💡 Hint

Common Mistakes

Using bitwise OR instead of AND.

Shifting bits in the wrong direction.

Shift 1 left by 3 to target the 4th bit, then use bitwise AND to check if it is set.

5fill in blank

hard

Fill all three blanks to toggle the 5th bit of variable flags.

C

flags = flags [1] (1 [2] [3]);

Drag options to blanks, or click blank then click option'

A&

B^

C<<

D4

Attempts:

3 left

💡 Hint

Common Mistakes

Using AND (&) which clears bits.

Using OR (|) which sets bits.

Use XOR (^) with 1 shifted left by 4 to toggle the 5th bit.