Accessing arguments - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to access the first command-line argument.

C

#include <stdio.h>

int main(int argc, char *argv[]) {
    printf("First argument: %s\n", argv[[1]]);
    return 0;
}

Drag options to blanks, or click blank then click option'

A1

Bargc

C2

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using argv[0] which is the program name, not the first argument.

Using argc as an index which is invalid.

The first command-line argument is stored at argv[1]. argv[0] is the program name.

2fill in blank

medium

Complete the code to check if at least two arguments are passed.

C

#include <stdio.h>

int main(int argc, char *argv[]) {
    if (argc [1] 3) {
        printf("Two or more arguments provided.\n");
    } else {
        printf("Less than two arguments.\n");
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

A>=

B<

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Checking if argc == 2 which means only one argument.

Using < instead of >= causing wrong condition.

Since argc counts the program name, at least two arguments means argc >= 3.

3fill in blank

hard

Fix the error in accessing the last argument.

C

#include <stdio.h>

int main(int argc, char *argv[]) {
    printf("Last argument: %s\n", argv[[1]]);
    return 0;
}

Drag options to blanks, or click blank then click option'

Aargc + 1

Bargc - 1

Cargc

Dargc - 2

Attempts:

3 left

💡 Hint

Common Mistakes

Using argc as index which is out of bounds.

Using argc + 1 which is invalid index.

The last argument is at index argc - 1 because argc counts all arguments including the program name.

4fill in blank

hard

Fill both blanks to print all arguments except the program name.

C

#include <stdio.h>

int main(int argc, char *argv[]) {
    for (int i = [1]; i [2] argc; i++) {
        printf("Argument %d: %s\n", i, argv[i]);
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

A1

B0

C<

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Starting loop at 0 which prints program name.

Using <= which causes out of bounds access.

Start from 1 to skip program name, and loop while i < argc to stay within bounds.

5fill in blank

hard

Fill all three blanks to print the number of arguments excluding the program name.

C

#include <stdio.h>

int main(int argc, char *argv[]) {
    int count = argc [1] [2];
    printf("Number of arguments: %d\n", [3]);
    return 0;
}

Drag options to blanks, or click blank then click option'

A-

B1

Ccount

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Adding 1 instead of subtracting.

Printing argc instead of count.

Subtract 1 from argc to exclude the program name, then print the count variable.