[Solved] Identify the error in the following C code snippet:void func() { printf("%d", x); } int main() { int x = 5; func(); return 0; } | C

C - Variables and Data Types

Identify the error in the following C code snippet:

void func() {
    printf("%d", x);
}
int main() {
    int x = 5;
    func();
    return 0;
}

Ax is not declared globally, so func() cannot access it

BVariable x is used before declaration in func()

CMissing return type for main()

DSyntax error in printf statement

Step-by-Step Solution

Solution:

Step 1: Check variable x usage in func()
func() tries to print x but x is declared only inside main(), so func() cannot see it.
Step 2: Understand variable scope rules
Variables declared inside main() are local to main() only, not visible in other functions.
Final Answer:
x is not declared globally, so func() cannot access it -> Option A
Quick Check:
Local variables not visible outside their function [OK]

Quick Trick: Functions can't access locals from other functions [OK]

Common Mistakes:

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