[Solved] Identify the error in this C program:#include <stdio.h> int main() { int num = 20; printf("%d", num) return 0; } | C

C - Basics and Execution Environment

Identify the error in this C program:

#include <stdio.h>
int main() {
    int num = 20;
    printf("%d", num)
    return 0;
}

AMissing semicolon after printf statement

BIncorrect format specifier in printf

CVariable 'num' not declared

DMissing return type for main

Step-by-Step Solution

Solution:

Step 1: Check syntax line by line
The printf statement lacks a semicolon at the end.
Step 2: Confirm other parts
Variable declaration and format specifier are correct; main has return type.
Final Answer:
Missing semicolon after printf statement -> Option A
Quick Check:
Every statement must end with a semicolon [OK]

Quick Trick: Always end statements with semicolon [OK]

Common Mistakes:

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