[Solved] Identify the error in this loop code:int i = 0; while (i — Ans: Missing increment of i inside the loop | C

C - Loops

Identify the error in this loop code:

int i = 0;
while (i < 5) {
    printf("%d ", i);
}

AIncorrect printf format specifier

BMissing increment of i inside the loop

CCondition should be i <= 5

DVariable i should be declared inside the loop

Step-by-Step Solution

Solution:

Step 1: Check loop body for changes to i
The variable i is never incremented inside the loop, so i stays 0 forever.
Step 2: Understand loop consequence
Without increment, the condition i < 5 is always true, causing an infinite loop.
Final Answer:
Missing increment of i inside the loop -> Option B
Quick Check:
Infinite loop due to no i++ [OK]

Quick Trick: Always update loop variable to avoid infinite loops [OK]

Common Mistakes:

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