[Solved] Consider this code snippet:int main() { int i = 0; loop: if (i == 5) goto end; printf("%d ", i); i++; goto loop; end: return 0; }What is the output and why? | C

C - Loop Control Statements

Consider this code snippet:

int main() {
    int i = 0;
    loop:
    if (i == 5) goto end;
    printf("%d ", i);
    i++;
    goto loop;
    end:
    return 0;
}

What is the output and why?

A0 1 2 3 4 5 , because i==5 is printed

B0 1 2 3 4 , because loop stops at i==5

CInfinite loop, because goto loops endlessly

DCompilation error due to label placement

Step-by-Step Solution

Solution:

Step 1: Trace the loop and condition
Loop prints i from 0 to 4. When i==5, goto jumps to end, stopping loop.
Step 2: Confirm output
Numbers 0 1 2 3 4 printed with spaces, no 5 printed.
Final Answer:
0 1 2 3 4 , because loop stops at i==5 -> Option B
Quick Check:
Goto breaks loop at condition [OK]

Quick Trick: Goto can break loops early with condition [OK]

Common Mistakes:

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