What will be the output of this C code?

medium📝 Predict Output Q13 of 15

C - Loop Control Statements

int main() {
    int x = 0;
    start:
    x++;
    if (x < 3) goto start;
    printf("%d", x);
    return 0;
}

DInfinite loop

Step-by-Step Solution

Solution:

Step 1: Trace the loop with goto
The label start is before x++. The code increments x, then checks if x < 3. If yes, it jumps back to start.
Step 2: Count increments until condition fails
x starts at 0, increments to 1, 2, then 3. When x is 3, condition x < 3 is false, so it stops looping and prints 3.
Final Answer:
3 -> Option A
Quick Check:
Loop increments x to 3 before printing [OK]

Quick Trick: Count increments until condition fails [OK]

Common Mistakes:

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