transaction with keys sender, receiver, and amount with exact valuesfee and set it to the exact value 0.001full_transaction that includes all keys from transaction plus the feefull_transaction dictionaryJump into concepts and practice - no test required
transaction with keys sender, receiver, and amount with exact valuesfee and set it to the exact value 0.001full_transaction that includes all keys from transaction plus the feefull_transaction dictionarytransaction with these exact entries: 'sender': '0xABC123', 'receiver': '0xDEF456', and 'amount': 10.Use curly braces to create a dictionary with the keys and values exactly as shown.
fee and set it to the float value 0.001.Just assign the number 0.001 to the variable named fee.
full_transaction that contains all keys and values from transaction plus a new key 'fee' with the value from the variable fee.Use dictionary unpacking {**transaction, 'fee': fee} to add the fee key.
print statement to display the full_transaction dictionary.Use print(full_transaction) to show the transaction details.
What is the main purpose of sending a transaction on a blockchain?
Which of the following is the correct way to sign a transaction before sending it?
transaction.sign(____)Consider this code snippet sending a transaction:
tx = {
'to': '0xabc123',
'value': 10,
'nonce': 5,
'gas': 21000
}
signed_tx = sign_transaction(tx, private_key)
result = send_transaction(signed_tx)
print(result)What will print(result) most likely output if the nonce is incorrect?
Given this code snippet, what is the main error preventing the transaction from sending?
tx = {
'to': '0xdef456',
'value': 5,
'nonce': 3
}
signed_tx = sign_transaction(tx, private_key)
result = send_transaction(signed_tx)
print(result)Options:
You want to send multiple transactions quickly from the same account. Which approach ensures all transactions are accepted without nonce conflicts?
1. Use the same nonce for all transactions
2. Increment nonce by 1 for each transaction
3. Use random nonce values
4. Skip nonce and rely on network