Why process control manages execution in Bash Scripting - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to run a command in the background.

Bash Scripting

sleep 10 [1]

Drag options to blanks, or click blank then click option'

A&

B&&

C|

D;

Attempts:

3 left

💡 Hint

Common Mistakes

Using '&&' runs the next command only if the first succeeds, not backgrounding.

Using '|' pipes output, not backgrounding.

Using ';' runs commands sequentially, not backgrounding.

Adding & at the end of a command runs it in the background, allowing the shell to continue without waiting.

2fill in blank

medium

Complete the code to wait for a background process to finish.

Bash Scripting

sleep 5 &
[1]

Drag options to blanks, or click blank then click option'

Akill

Bwait

Cexit

Dstop

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'stop' does not wait for processes.

Using 'kill' terminates processes instead of waiting.

Using 'exit' ends the script immediately.

The wait command pauses the script until all background jobs finish.

3fill in blank

hard

Fix the error in the code to correctly bring a background job to the foreground.

Bash Scripting

sleep 20 &
[1]

Drag options to blanks, or click blank then click option'

Ajobs 1

Bbg 1

Cfg 1

Dkill 1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'bg' keeps the job in the background.

Using 'jobs' lists jobs but does not bring them forward.

Using 'kill' terminates the job.

The fg command brings a background job to the foreground. The number 1 refers to the job ID.

4fill in blank

hard

Fill both blanks to create a loop that runs a command and waits for it to finish before continuing.

Bash Scripting

for i in {1..3}; do
  sleep 2 [1]
  [2]
  echo "Done $i"
done

Drag options to blanks, or click blank then click option'

A&

Bwait

Cfg

Dkill

Attempts:

3 left

💡 Hint

Common Mistakes

Not using '&' causes the loop to wait naturally, no need for wait.

Using 'fg' does not wait but brings jobs to foreground.

Using 'kill' stops the process.

Running sleep 2 & starts the sleep in the background, and wait pauses until it finishes before echoing.

5fill in blank

hard

Fill all three blanks to create a dictionary-like output of job IDs and their statuses.

Bash Scripting

jobs_output=$(jobs)
while read -r line; do
  job_id=$(echo $line | awk [1])
  status=$(echo $line | awk [2])
  echo "Job $[3]: $status"
done <<< "$jobs_output"

Drag options to blanks, or click blank then click option'

A'{print $1}'

B'{print $2}'

Cjob_id

Dstatus

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up field numbers in awk.

Using variable names incorrectly in echo.

Not reading the jobs output line properly.

The first awk prints the job ID (first field), the second prints the status (second field), and the echo uses the job_id variable.