Why patterns solve common automation needs in Bash Scripting - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print all files in the current directory.

Bash Scripting

for file in [1]; do echo "$file"; done

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A*

Becho

Cpwd

Dls

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'ls' directly in the loop variable, which causes errors.

Using 'pwd' which prints the current directory path, not files.

The asterisk (*) matches all files in the current directory, so the loop prints each file name.

2fill in blank

medium

Complete the code to check if a file named 'data.txt' exists.

Bash Scripting

if [[ [1] "data.txt" ]]; then echo "File exists"; fi

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A-f

B-e

C-s

D-d

Attempts:

3 left

💡 Hint

Common Mistakes

Using '-d' which checks for directories only.

Using '-s' which checks if file size is greater than zero.

The '-e' option checks if the file exists, regardless of type.

3fill in blank

hard

Fix the error in the code to count lines in 'log.txt'.

Bash Scripting

count=$(cat log.txt | [1] -l)

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Als

Bgrep

Cwc

Dhead

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'ls -l' which lists files, not lines.

Using 'grep -l' which lists filenames matching a pattern.

'wc -l' counts the number of lines in the input. The original code misses the command 'wc'.

4fill in blank

hard

Fill both blanks to create a loop that prints numbers 1 to 5.

Bash Scripting

for num in [1]; do echo [2]; done

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A{1..5}

Bnum

C$num

D1 2 3 4 5

Attempts:

3 left

💡 Hint

Common Mistakes

Printing 'num' without '$' prints the word 'num' literally.

Using 'num' instead of a sequence in the loop.

'{1..5}' generates numbers 1 to 5. '$num' prints the current number in the loop.

5fill in blank

hard

Fill all three blanks to create a dictionary-like structure with file sizes.

Bash Scripting

declare -A sizes
for file in [1]; do sizes[[2]]=$(stat -c [3] "$file"); done
for f in "${!sizes[@]}"; do echo "$f: ${sizes[$f]} bytes"; done

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A*

Bfile

C%s

D%n

Attempts:

3 left

💡 Hint

Common Mistakes

Using '%n' which returns the file name, not size.

Using incorrect keys in the associative array.

'*' matches all files. 'file' is the key for the associative array. '%s' gets file size in bytes with stat.