Basic regex in grep in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to search for the word 'error' in the file 'log.txt'.

Bash Scripting

grep [1] log.txt

Drag options to blanks, or click blank then click option'

A-i 'error'

B'error'

C'Error'

D-v 'error'

Attempts:

3 left

💡 Hint

Common Mistakes

Using -v option which inverts the match.

Using -i which ignores case, but the task wants exact match.

The command grep 'error' log.txt searches for the exact word 'error' in the file.

2fill in blank

medium

Complete the code to search for lines starting with 'Error' in 'log.txt'.

Bash Scripting

grep [1] log.txt

Drag options to blanks, or click blank then click option'

A'Error$'

B'^error'

C'Error'

D'^Error'

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'Error$' which matches lines ending with 'Error'.

Not using ^ so matches anywhere in the line.

The caret ^ means the line starts with the pattern 'Error'.

3fill in blank

hard

Fix the error in the code to search for lines containing digits in 'data.txt'.

Bash Scripting

grep [1] data.txt

Drag options to blanks, or click blank then click option'

A'[0-9]'

B'[a-z]'

C'\\d'

D'[A-Z]'

Attempts:

3 left

💡 Hint

Common Mistakes

Using '\d' which is not recognized by basic grep.

Using character classes that do not include digits.

The pattern '[0-9]' matches any digit. '\d' is not supported by basic grep regex.

4fill in blank

hard

Fill both blanks to create a grep command that finds lines with exactly three digits in a row in 'file.txt'.

Bash Scripting

grep [1][2] file.txt

Drag options to blanks, or click blank then click option'

A'[0-9]'

B'\\{3\\}'

C'[a-z]'

D'\\{2\\}'

Attempts:

3 left

💡 Hint

Common Mistakes

Using '\{2\}' which matches two digits instead of three.

Using '[a-z]' which matches letters, not digits.

The pattern '[0-9]\{3\}' matches exactly three digits in a row in basic grep regex.

5fill in blank

hard

Fill all three blanks to create a grep command that finds lines starting with 'ID' followed by one or more digits in 'records.txt'.

Bash Scripting

grep [1][2][3] records.txt

Drag options to blanks, or click blank then click option'

A'^ID'

B'[0-9]'

C'\\+'

D'\\{1,\\}'

Attempts:

3 left

💡 Hint

Common Mistakes

Using '\+' which is not supported in basic grep regex.

Not anchoring the pattern with '^' to match start of line.

The pattern '^ID[0-9]\{1,\}' matches lines starting with 'ID' followed by one or more digits in basic grep regex.