Why string manipulation is frequent in Bash Scripting - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print the length of the string stored in variable 'text'.

Bash Scripting

echo ${#[1]

Drag options to blanks, or click blank then click option'

Atext

Blength

Cstr

Dlen

Attempts:

3 left

💡 Hint

Common Mistakes

Using function names like 'len' or 'length' instead of variable name.

Forgetting to use ${#} syntax.

The syntax ${#variable} returns the length of the string stored in variable. Here, text is the variable holding the string.

2fill in blank

medium

Complete the code to extract the first 4 characters from the string in variable 'word'.

Bash Scripting

echo ${word:[1]:4}

Drag options to blanks, or click blank then click option'

A1

B0

C4

D-1

Attempts:

3 left

💡 Hint

Common Mistakes

Starting at 1 which skips the first character.

Using negative indexes which are not supported in this syntax.

In bash, ${variable:start:length} extracts a substring. Starting at index 0 extracts from the beginning.

3fill in blank

hard

Fix the error in the code to replace all occurrences of 'a' with 'o' in variable 'text'.

Bash Scripting

echo ${text//[1]/o}

Drag options to blanks, or click blank then click option'

Ab

Bd

Cc

Da

Attempts:

3 left

💡 Hint

Common Mistakes

Using a wrong letter in the pattern.

Using single slash / which replaces only first occurrence.

The syntax ${variable//pattern/replacement} replaces all occurrences of pattern with replacement. Here, 'a' is replaced by 'o'.

4fill in blank

hard

Fill both blanks to create a substring from variable 'data' starting at index 2 with length 5.

Bash Scripting

echo ${data:[1]:[2]

Drag options to blanks, or click blank then click option'

A2

B3

C5

D4

Attempts:

3 left

💡 Hint

Common Mistakes

Swapping start and length values.

Using wrong indexes causing unexpected substring.

The syntax ${variable:start:length} extracts a substring. Here, start is 2 and length is 5.

5fill in blank

hard

Fill all three blanks to create a new string with 'Hello' replaced by 'Hi' in variable 'greeting', then print its length.

Bash Scripting

new=${greeting/[1]/[2]
echo ${#[3]

Drag options to blanks, or click blank then click option'

AHello

BHi

Cnew

Dgreeting

Attempts:

3 left

💡 Hint

Common Mistakes

Printing length of original variable instead of new.

Using wrong replacement strings.

First, replace 'Hello' with 'Hi' in 'greeting' and store in 'new'. Then print length of 'new' using ${#new}.