Why arrays handle lists of data in Bash Scripting - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create an array named 'fruits' with three items.

Bash Scripting

fruits=([1])

Drag options to blanks, or click blank then click option'

A"apple" "banana" "cherry"

B"apple, banana, cherry"

Capple banana cherry

D[apple banana cherry]

Attempts:

3 left

💡 Hint

Common Mistakes

Using commas between items inside the array.

Putting the entire list inside quotes as one string.

Using square brackets instead of parentheses.

In bash, arrays are created by listing items separated by spaces inside parentheses without quotes around the whole list.

2fill in blank

medium

Complete the code to print the second item in the 'fruits' array.

Bash Scripting

echo ${fruits[1]

Drag options to blanks, or click blank then click option'

A[2]

B[1]

C[0]

D[3]

Attempts:

3 left

💡 Hint

Common Mistakes

Using index 2 to get the second item.

Forgetting to use curly braces around the variable.

Using parentheses instead of square brackets.

Array indexes in bash start at 0, so the second item is at index 1.

3fill in blank

hard

Fix the error in the code to add 'orange' to the end of the 'fruits' array.

Bash Scripting

fruits+=([1])

Drag options to blanks, or click blank then click option'

A"orange"

Borange

C'orange'

D[orange]

Attempts:

3 left

💡 Hint

Common Mistakes

Not using quotes causing syntax errors.

Using square brackets which are invalid here.

Using single quotes which also work but double quotes are preferred.

When adding a string with special characters or spaces, quotes are needed. Here, double quotes are preferred.

4fill in blank

hard

Fill both blanks to loop over the 'fruits' array and print each item.

Bash Scripting

for [1] in "${fruits[2]"; do
  echo $[1]
done

Drag options to blanks, or click blank then click option'

Afruit

B[@]

C[*]

Ditem

Attempts:

3 left

💡 Hint

Common Mistakes

Using [*] which treats all items as one string.

Using invalid variable names.

Forgetting quotes around the array expansion.

Use a variable name like 'fruit' for each item, and "${fruits[@]}" to loop over all items individually.

5fill in blank

hard

Fill all three blanks to create an associative array 'colors' with keys and values, then print the value for key 'apple'.

Bash Scripting

declare -A colors=([1])
echo ${colors[2]
colors[banana]=[3]

Drag options to blanks, or click blank then click option'

A[apple]=red [banana]=yellow

B[apple]

Cgreen

D[banana]

Attempts:

3 left

💡 Hint

Common Mistakes

Not using declare -A for associative arrays.

Using parentheses without brackets for keys.

Forgetting to use brackets when accessing or assigning.

Associative arrays use declare -A and key-value pairs in brackets. To print a value, use the key in brackets. To assign, use the key in brackets and set the value.