[Solved] Why does this code produce no output?var="file." echo ${var#*.} - Ans: Because the pattern '*.' matches the entire string and removes all | Bash Scripting

Bash Scripting - String Operations

Why does this code produce no output?

var="file."
echo ${var#*.}

ABecause the pattern '*.' does not match any prefix

BBecause the variable is empty

CBecause the pattern '*.' matches the entire string and removes all

DBecause the pattern '*.' is invalid syntax

Step-by-Step Solution

Solution:

Step 1: Analyze the pattern '*.'
The pattern '*.' matches the shortest prefix ending with '.'. Here, the entire 'file.' matches.
Step 2: Remove the matched prefix
Removing the entire string leaves nothing, so no output.
Final Answer:
Because the pattern '*.' matches the entire string and removes all -> Option C
Quick Check:
Pattern '*.' matches entire 'file.', output empty [OK]

Quick Trick: Pattern can remove entire string if it matches full prefix [OK]

Common Mistakes:

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