[Solved] Consider this script snippet:mkdir test_dir false if [ $? -eq 0 ]; then echo "Created" else echo "Failed" fiWhat is the problem if the script always prints "Failed" even when the directory is created? | Bash Scripting

Bash Scripting - Error Handling

Consider this script snippet:

mkdir test_dir
false
if [ $? -eq 0 ]; then
  echo "Created"
else
  echo "Failed"
fi

What is the problem if the script always prints "Failed" even when the directory is created?

Amkdir command does not set exit code

BThe syntax of if statement is wrong

CThe <code>$?</code> is checked too late after mkdir

Decho command overwrites the exit code

Step-by-Step Solution

Solution:

Step 1: Understand exit code timing
The exit code $? must be checked immediately after the command it relates to.
Step 2: Identify delay in checking exit code
If any command runs between mkdir and checking $?, the exit code changes.
Final Answer:
The $? is checked too late after mkdir -> Option C
Quick Check:
Check $? immediately after command [OK]

Quick Trick: Check $? right after command, no commands in between [OK]

Common Mistakes:

MISTAKES

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