String length (${#var}) in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print the length of the string stored in variable name.

Bash Scripting

echo [1]

Drag options to blanks, or click blank then click option'

A$name

B$#name

C${name#}

D${#name}

Attempts:

3 left

💡 Hint

Common Mistakes

Using just $name prints the string, not its length.

Using ${name#} is incorrect syntax for length.

Using $#name is invalid in this context.

In bash, ${#var} gives the length of the string stored in var. So ${#name} prints the length of name.

2fill in blank

medium

Complete the code to store the length of word into variable len.

Bash Scripting

len=[1]

Drag options to blanks, or click blank then click option'

A${word#}

B$word

C${#word}

D$#word

Attempts:

3 left

💡 Hint

Common Mistakes

Assigning len=$word stores the string, not its length.

Using ${word#} is invalid for length.

Using $#word is incorrect syntax.

Assigning len=${#word} stores the length of word in len.

3fill in blank

hard

Fix the error in the code to correctly print the length of text.

Bash Scripting

echo [1]

Drag options to blanks, or click blank then click option'

A${#text}

B${text#}

C$#text

D${text}

Attempts:

3 left

💡 Hint

Common Mistakes

Using ${text} prints the string, not its length.

Using $#text is invalid syntax.

Using ${text#} is incorrect.

Only ${#text} correctly prints the length of the string stored in text.

4fill in blank

hard

Fill both blanks to create a loop that prints each word and its length from the list words.

Bash Scripting

for word in [1]; do
  echo "$word: $[2]"
done

Drag options to blanks, or click blank then click option'

A"${words[@]}"

B${#word}

C${word}

Dwords

Attempts:

3 left

💡 Hint

Common Mistakes

Using just words without quotes or array syntax causes errors.

Using ${word} instead of ${#word} prints the word, not its length.

The loop iterates over all elements in the array words using "${words[@]}". Inside the loop, ${#word} gives the length of the current word.

5fill in blank

hard

Fill all three blanks to create a dictionary-like output of words and their lengths from list.

Bash Scripting

declare -A lengths
for [1] in [2]; do
  lengths[[1]]=[3]
done
for key in "${!lengths[@]}"; do
  echo "$key: ${lengths[$key]}"
done

Drag options to blanks, or click blank then click option'

Aitem

B"${list[@]}"

C${#item}

Dlist

Attempts:

3 left

💡 Hint

Common Mistakes

Using list without quotes or array syntax causes errors.

Using ${item} instead of ${#item} stores the word, not its length.

Using inconsistent variable names inside the loop.

The loop uses item as the variable, iterates over all elements in list with "${list[@]}", and stores the length of each item with ${#item}.