Local variables (local keyword) in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare a local variable inside the function.

Bash Scripting

my_function() {
  [1] my_var="Hello"
  echo "$my_var"
}

Drag options to blanks, or click blank then click option'

Alocal

Bglobal

Cdeclare

Dvar

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'global' instead of 'local' which is not valid in bash.

Using 'var' which is not a bash keyword.

Using 'declare' without the local keyword does not limit scope.

The 'local' keyword declares a variable that is only visible inside the function.

2fill in blank

medium

Complete the code to print the local variable inside the function.

Bash Scripting

function greet() {
  local message="Hi"
  echo [1]
}
greet

Drag options to blanks, or click blank then click option'

Amessage

B$message

C"message"

D'message'

Attempts:

3 left

💡 Hint

Common Mistakes

Printing the variable name without $ which outputs the name, not the value.

Using quotes around the variable name which prints the literal string.

To print the value of a variable in bash, prefix it with a dollar sign ($).

3fill in blank

hard

Fix the error in the function by declaring the variable local.

Bash Scripting

count=5
increment() {
  [1] count=$((count + 1))
  echo $count
}
increment
 echo $count

Drag options to blanks, or click blank then click option'

Aexport

Bglobal

Clocal

Ddeclare

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'global' which is not a bash keyword.

Using 'export' which affects environment variables, not local scope.

Declaring 'count' as local inside the function prevents changing the global variable.

4fill in blank

hard

Fill both blanks to declare a local variable and assign it a value.

Bash Scripting

my_func() {
  [1] [2]="World"
  echo "$greeting"
}
my_func

Drag options to blanks, or click blank then click option'

Alocal

Bgreeting

Cmessage

Dvar

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'var' which is not a bash keyword.

Using a variable name different from the one echoed.

Use 'local' to declare the variable and 'greeting' as the variable name.

5fill in blank

hard

Fill all three blanks to declare a local variable, assign it, and print it.

Bash Scripting

function say() {
  [1] [2]="Hello"
  echo [3]
}
say

Drag options to blanks, or click blank then click option'

Alocal

Bgreet

C$greet

Dmessage

Attempts:

3 left

💡 Hint

Common Mistakes

Not using local keyword.

Printing variable name without $.

Using different variable names inconsistently.

Declare 'greet' as local, assign it, and print its value with $.