[Solved] Identify the error in this Bash function:myfunc() { local 1var=100 echo $1var } myfunc - Ans: Variable name cannot start with a digit | Bash Scripting

Bash Scripting - Functions

Identify the error in this Bash function:

myfunc() {
  local 1var=100
  echo $1var
}
myfunc

AMissing semicolon after local declaration

BVariable name cannot start with a digit

Clocal keyword cannot be used inside functions

DEcho command syntax is incorrect

Step-by-Step Solution

Solution:

Step 1: Check variable naming rules
Variable names cannot start with digits in Bash.
Step 2: Analyze code
local 1var=100 is invalid due to starting digit.
Step 3: Other options
Semicolon not required; local is valid inside functions; echo syntax is correct.
Final Answer:
Variable name cannot start with a digit -> Option B
Quick Check:
Variable names must start with letter or underscore [OK]

Quick Trick: Variable names cannot begin with digits [OK]

Common Mistakes:

MISTAKES

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